@@ -379,7 +379,6 @@ static bool unifyConcreteTypes(
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// / When a type parameter has two superclasses, we have to both unify the
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// / type constructor arguments, and record the most derived superclass.
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// /
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- // /
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// / For example, if we have this setup:
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// /
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// / class Base<T, T> {}
@@ -544,7 +543,7 @@ PropertyMap::~PropertyMap() {
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clear ();
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}
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- // / Look for an property bag corresponding to a suffix of the given key.
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+ // / Look for a property bag corresponding to a suffix of the given key.
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// /
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// / Returns nullptr if no information is known about this key.
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PropertyBag *
@@ -555,7 +554,7 @@ PropertyMap::lookUpProperties(const MutableTerm &key) const {
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return nullptr ;
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}
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- // / Look for an property bag corresponding to the given key, creating a new
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+ // / Look for a property bag corresponding to the given key, creating a new
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// / property bag if necessary.
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// /
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// / This must be called in monotonically non-decreasing key order.
@@ -567,7 +566,7 @@ PropertyMap::getOrCreateProperties(Term key) {
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auto *props = new PropertyBag (key);
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- // Look for the longest suffix of the key that has an property bag,
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+ // Look for the longest suffix of the key that has a property bag,
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// recording it as the next property bag if we find one.
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//
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// For example, if our rewrite system contains the following three rules:
@@ -841,7 +840,7 @@ void PropertyMap::concretizeNestedTypesFromConcreteParent(
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}
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}
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- // / Given the key of an property bag known to have \p concreteType,
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+ // / Given the key of a property bag known to have \p concreteType,
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// / together with a \p typeWitness from a conformance on that concrete
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// / type, return the right hand side of a rewrite rule to relate
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// / \p subjectType with a term representing the type witness.
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