updates question 1.2,1.3,1.4. Adding 1.5 start

Author: camilosalazar98

Python/chapter01/1.4 - PalinPerm/camilo_solution_1.4.py

@@ -0,0 +1,28 @@
+"""
+Palindrome Permutation: Given a string, write a function to check if it is a
+permutation of a palin­ drome. A palindrome is a word or phrase that is the same
+forwards and backwards. A permutation is a rearrangement of letters.
+The palindrome does not need to be limited to just dictionary words.
+EXAMPLE
+Input: Tact Coa
+Output: True (permutations: "taco cat", "atco eta", etc.)
+"""
+
+def PalinPerm(str):
+    d = {}
+    str = str.replace(' ','').lower()#Take out the spaces
+    for i in str:
+        if i in d:
+            d[i] += 1
+        else:
+            d[i] = 1
+    odd_count = 0 # pop ppo opp
+    for keys,value in d.items():
+        if value % 2 != 0 and odd_count == 0:# Remeber there should only be 1 where key equals when val%2
+            odd_count += 1
+        elif value % 2 != 0 and odd_count != 0:
+            return False
+    return True
+
+print(PalinPerm('taco cat'))#True
+print(PalinPerm('taco catt'))#False