The generated file is named "_" (underscore)

[wiiznokes]

Here is the code:

prost_build::Config::new()
        .out_dir("src/streamer")
        .compile_protos(&["src/proto/message.proto"], &["src/proto"])
        .expect("Failed to compile protobuf files");

and the .proto file:

syntax = "proto3";

message AudioPacketMessage {
  bytes buffer = 1;
  uint32 sample_rate = 2;
  uint32 channel_count = 3;
  uint32 audio_format = 4;
}

message AudioPacketMessageOrdered {
  uint32 sequence_number = 1;
  AudioPacketMessage audio_packet = 2;
}

message ConnectMessage {}

message MessageWrapper {
  oneof payload {
    AudioPacketMessageOrdered audio_packet = 1;
    ConnectMessage connect = 2;
  }
}

let me know if you need more information

[soumyasen1809]

You need to provide a package name to your proto file. Something like:

syntax = "proto3";

package AudioPacketMessage;

message AudioPacketMessage {
  bytes buffer = 1;
  uint32 sample_rate = 2;
  uint32 channel_count = 3;
  uint32 audio_format = 4;
}

message AudioPacketMessageOrdered {
  uint32 sequence_number = 1;
  AudioPacketMessage audio_packet = 2;
}

message ConnectMessage {}

message MessageWrapper {
  oneof payload {
    AudioPacketMessageOrdered audio_packet = 1;
    ConnectMessage connect = 2;
  }
}

Your generated file will be audio_packet_message.rs.

[wiiznokes]

Ty,

Would be nice if it could fallback to the name of the proto file tho

[soumyasen1809]

prost/prost-build/src/config.rs

Line 1210 in fafa97f

default_package_filename: "_".to_string(),

The default package file name is "_"
Not sure if the Prost team would want a fallback to the proto file name.