fixed identation issue

Author: Anoop Kapoor

ggml/src/ggml.c

@@ -7256,7 +7256,7 @@ void ggml_perf_accumulate(struct ggml_perf_totals totals[GGML_OP_COUNT], struct
             enum ggml_unary_op subop = ggml_get_unary_op(node);
             totals[op].unary_subtotals[subop].total_us += node->perf_time_us;
             totals[op].unary_subtotals[subop].runs     += node->perf_runs;
-	    totals[op].unary_subtotals[subop].tsi_kernel_count   += node->tsi_kernel_runs;
+            totals[op].unary_subtotals[subop].tsi_kernel_count   += node->tsi_kernel_runs;
         }
     }
 }

src/llama-context.cpp

@@ -2801,11 +2801,11 @@ void ggml_perf_print_totals(struct ggml_perf_totals totals[GGML_OP_COUNT]) {
                     char padded_backend[7] = {0}; // 6 chars + null terminator
                     snprintf(padded_backend, sizeof(padded_backend), "%-6s", backend_name);
 
-		    LLAMA_LOG_TSAVORITE("  %-16s %-8s %7ld  %14ld  %16ld  %16.2f\n",
+                    LLAMA_LOG_TSAVORITE("  %-16s %-8s %7ld  %14ld  %16ld  %16.2f\n",
                         totals[i].op_name ? totals[i].op_name : "UNKNOWN",
                         padded_backend,
                         totals[i].backend_subtotals[b].runs,
-			totals[i].backend_subtotals[b].tsi_kernel_count,
+                        totals[i].backend_subtotals[b].tsi_kernel_count,
                         totals[i].backend_subtotals[b].total_us,
                         (double)totals[i].backend_subtotals[b].total_us / totals[i].backend_subtotals[b].runs);
                 }
@@ -2831,7 +2831,7 @@ void ggml_perf_print_totals(struct ggml_perf_totals totals[GGML_OP_COUNT]) {
                             ggml_unary_op_name((enum ggml_unary_op) j),
                             padded_backend,
                             totals[i].unary_subtotals[j].runs,
-			    totals[i].unary_subtotals[j].tsi_kernel_count,
+                            totals[i].unary_subtotals[j].tsi_kernel_count,
                             totals[i].unary_subtotals[j].total_us,
                             (double)totals[i].unary_subtotals[j].total_us / totals[i].unary_subtotals[j].runs);
                     }