Why the App exit loop after run()?? #1300
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wengjianhong
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when I use this code:
But if I call SocketApp.run(); by this code, the run() function will run over soon, and loop will exit soon, too.
In other word, the socketApp will not run server ok.
why??
In addition, I try define the SocketApp as global variable, the server run OK, if I define the SocketApp as local variable, the server can't run ok.
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