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pointUpdateRangeSumQuery.cpp
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64 lines (57 loc) · 1.46 KB
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/*
Given an array of size and some queries. There are two types of queries:
Update: Given and , update array element A[idx] as A[idx] = A[idx]+val.
Query: Given l and r return the value of A[l]+A[l+1]+...+A[r-1]+A[r] such that
0<=l<=r<N.
*/
const ll N = 100;
ll A[N];
ll tree[4 * N];
void build(ll node, ll start, ll end) {
if (start == end) {
tree[node] = A[start];
} else {
ll mid = (start + end) / 2;
build(2 * node, start, mid);
build(2 * node + 1, mid + 1, end);
tree[node] = tree[2 * node] + tree[2 * node + 1];
}
}
void update(ll node, ll start, ll end, ll idx, ll val) {
if (start == end) {
A[idx] += val;
tree[node] += val;
} else {
ll mid = (start + end) / 2;
if (idx >= start && idx <= mid) {
update(2 * node, start, mid, idx, val);
} else {
update(2 * node + 1, mid + 1, end, idx, val);
}
tree[node] = tree[2 * node] + tree[2 * node + 1];
}
}
ll query(ll node, ll start, ll end, ll l, ll r) {
if (r < start || l > end) {
return 0;
} else if (l <= start && r >= end) {
return tree[node];
} else {
ll mid = (start + end) / 2;
ll lq = query(2 * node, start, mid, l, r);
ll rq = query(2 * node + 1, mid + 1, end, l, r);
return (lq + rq);
}
}
int main() {
ll n;
cin >> n;
ll node = 1, start = 0, end = n - 1;
for (ll i = 0; i < n; i++) {
cin >> A[i];
}
build(node, start, end);
ll ans = query(node, start, end, 2, 3);
cout << ans << endl;
return 0;
}