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虽然的确简单,但是wp里一句话略过还是有点点草率
这里提供一个闭着眼睛两分钟敲出来的解题脚本的核心部分
char temp_password[9];
char Upassword[] = {68, 0, 2, 65, 67, 71, 16, 99, 0};
temp_password[8] = '\x00';
int i;
for (i = 7; i >= 0; --i) {
for(int ii = 48;ii <= 123;ii++) {
temp_password[i] = ii;
temp_password[i] =
((temp_password[i] | temp_password[i + 1]) & ~(temp_password[i] & temp_password[i + 1]) | i) &
~((temp_password[i] | temp_password[i + 1]) & ~(temp_password[i] & temp_password[i + 1]) & i);
if (temp_password[i] == Upassword[i]) {
temp_password[i] = ii;
printf("%c", ii);
break;
}
}
}
那么它最主要地 有什么不好呢?
输出的结果是反着的
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