[clang] Don't evaluate the initializer of constexpr-unknown parameters. (llvm#142498)

If we see a parameter of reference type that isn't part of the frame,
don't try to evaluate its default argument. Just treat it as a
constexpr-unknown value.

Fixes llvm#141114.  Fixes llvm#141858.

Author: efriedma-quic

clang/lib/AST/ExprConstant.cpp

@@ -3550,7 +3550,12 @@ static bool evaluateVarDeclInit(EvalInfo &Info, const Expr *E,
   // should begin within the evaluation of E
   // Used to be C++20 [expr.const]p5.12.2:
   // ... its lifetime began within the evaluation of E;
-  if (isa<ParmVarDecl>(VD) && !AllowConstexprUnknown) {
+  if (isa<ParmVarDecl>(VD)) {
+    if (AllowConstexprUnknown) {
+      Result = &Info.CurrentCall->createConstexprUnknownAPValues(VD, Base);
+      return true;
+    }
+
     // Assume parameters of a potential constant expression are usable in
     // constant expressions.
     if (!Info.checkingPotentialConstantExpression() ||

clang/test/SemaCXX/constant-expression-p2280r4.cpp

@@ -250,3 +250,15 @@ namespace uninit_reference_used {
   // expected-note {{in call to 'g5()'}}
 
 }
+
+namespace param_reference {
+  constexpr int arbitrary = -12345;
+  constexpr void f(const int &x = arbitrary) { // expected-note {{declared here}}
+    constexpr const int &v1 = x; // expected-error {{must be initialized by a constant expression}} \
+    // expected-note {{reference to 'x' is not a constant expression}}
+    constexpr const int &v2 = (x, arbitrary); // expected-warning {{left operand of comma operator has no effect}}
+    constexpr int v3 = x; // expected-error {{must be initialized by a constant expression}}
+    static_assert(x==arbitrary); // expected-error {{static assertion expression is not an integral constant expression}}
+    static_assert(&x - &x == 0);
+  }
+}