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| 1 | +package com.study.sort; |
| 2 | + |
| 3 | +import java.util.Arrays; |
| 4 | + |
| 5 | +/** |
| 6 | + * 冒泡,选择,插入,快速,归并 |
| 7 | + * |
| 8 | + * @author ldb |
| 9 | + * @date 2019-10-08 16:09 |
| 10 | + */ |
| 11 | +public class Sorts { |
| 12 | + |
| 13 | + /** |
| 14 | + * 冒泡排序 |
| 15 | + * |
| 16 | + * @param arr |
| 17 | + */ |
| 18 | + public static void bubbleSort(int[] arr) { |
| 19 | + for (int i = 0; i < arr.length; i++) { |
| 20 | + for (int j = 0; j < arr.length - 1 - i; j++) { |
| 21 | + if (arr[j] > arr[j + 1]) { |
| 22 | + int temp = arr[j]; |
| 23 | + arr[j] = arr[j + 1]; |
| 24 | + arr[j + 1] = temp; |
| 25 | + } |
| 26 | + } |
| 27 | + } |
| 28 | + } |
| 29 | + |
| 30 | + /** |
| 31 | + * 优化冒泡排序 |
| 32 | + * |
| 33 | + * @param arr |
| 34 | + */ |
| 35 | + public static void bubbleSort2(int[] arr) { |
| 36 | + for (int i = 0; i < arr.length - 1; i++) { |
| 37 | + boolean flag = true; |
| 38 | + for (int j = 0; j < arr.length - 1 - i; j++) { |
| 39 | + if (arr[j] > arr[j + 1]) { |
| 40 | + int temp = arr[j]; |
| 41 | + arr[j] = arr[j + 1]; |
| 42 | + arr[j + 1] = temp; |
| 43 | + flag = false; |
| 44 | + } |
| 45 | + } |
| 46 | + if (flag) { |
| 47 | + break; |
| 48 | + } |
| 49 | + } |
| 50 | + } |
| 51 | + |
| 52 | + /** |
| 53 | + * 插入排序 |
| 54 | + * |
| 55 | + * @param arr |
| 56 | + */ |
| 57 | + public static void insertSort(int[] arr) { |
| 58 | + for (int i = 1; i < arr.length; i++) { |
| 59 | + int val = arr[i]; |
| 60 | + int index = i - 1; |
| 61 | + while (index >= 0 && arr[index] > val) { |
| 62 | + arr[index + 1] = arr[index]; |
| 63 | + index--; |
| 64 | + } |
| 65 | + arr[index + 1] = val; |
| 66 | + } |
| 67 | + } |
| 68 | + |
| 69 | + /** |
| 70 | + * 插入排序 |
| 71 | + * |
| 72 | + * @param arr |
| 73 | + * @param n 表示数组有用大小 |
| 74 | + */ |
| 75 | + public static void insertSort(int[] arr, int n) { |
| 76 | + for (int i = 1; i < n; i++) { |
| 77 | + int val = arr[i]; |
| 78 | + int index = i - 1; |
| 79 | + while (index >= 0 && arr[index] > val) { |
| 80 | + arr[index + 1] = arr[index]; |
| 81 | + index--; |
| 82 | + } |
| 83 | + arr[index + 1] = val; |
| 84 | + } |
| 85 | + } |
| 86 | + |
| 87 | + /** |
| 88 | + * 选择排序 |
| 89 | + * |
| 90 | + * @param arr |
| 91 | + */ |
| 92 | + public static void selectSort(int[] arr) { |
| 93 | + |
| 94 | + for (int i = 0; i < arr.length - 1; i++) { |
| 95 | + int minIndex = i; |
| 96 | + for (int j = i + 1; j < arr.length; j++) { |
| 97 | + if (arr[minIndex] > arr[j]) { |
| 98 | + minIndex = j; |
| 99 | + } |
| 100 | + } |
| 101 | + // 交换 |
| 102 | + int temp = arr[i]; |
| 103 | + arr[i] = arr[minIndex]; |
| 104 | + arr[minIndex] = temp; |
| 105 | + } |
| 106 | + } |
| 107 | + |
| 108 | + /** |
| 109 | + * 归并排序 |
| 110 | + * |
| 111 | + * @param arr |
| 112 | + */ |
| 113 | + public static void mergeSort(int[] arr, int left, int right) { |
| 114 | + if (left >= right) { |
| 115 | + return; |
| 116 | + } |
| 117 | + int q = (left + right) / 2; |
| 118 | + mergeSort(arr, left, q); |
| 119 | + mergeSort(arr, q + 1, right); |
| 120 | + merge2(arr, left, q, right); |
| 121 | + |
| 122 | + } |
| 123 | + |
| 124 | + private static void merge2(int[] arr, int left, int q, int right) { |
| 125 | + int[] leftArr = new int[q - left + 2]; |
| 126 | + int[] rightArr = new int[right - q + 1]; |
| 127 | + |
| 128 | + for (int i = 0; i <= q - left; i++) { |
| 129 | + leftArr[i] = arr[left + i]; |
| 130 | + } |
| 131 | + // 第一个数组添加哨兵(最大值) |
| 132 | + leftArr[q - left + 1] = Integer.MAX_VALUE; |
| 133 | + |
| 134 | + for (int i = 0; i < right - q; i++) { |
| 135 | + rightArr[i] = arr[q + 1 + i]; |
| 136 | + } |
| 137 | + // 第二个数组添加哨兵(最大值) |
| 138 | + rightArr[right - q] = Integer.MAX_VALUE; |
| 139 | + |
| 140 | + int i = 0; |
| 141 | + int j = 0; |
| 142 | + int k = left; |
| 143 | + while (k <= right) { |
| 144 | + // 当左边数组到达哨兵值时,i不再增加,直到右边数组读取完剩余值,同理右边数组也一样 |
| 145 | + if (leftArr[i] <= rightArr[j]) { |
| 146 | + arr[k++] = leftArr[i++]; |
| 147 | + } else { |
| 148 | + arr[k++] = rightArr[j++]; |
| 149 | + } |
| 150 | + } |
| 151 | + } |
| 152 | + |
| 153 | + private static void merge(int[] arr, int left, int q, int right) { |
| 154 | + int i = left; |
| 155 | + int j = q + 1; |
| 156 | + int k = 0; |
| 157 | + int[] tmp = new int[right - left + 1]; |
| 158 | + while (i <= q && j <= right) { |
| 159 | + if (arr[i] <= arr[j]) { |
| 160 | + tmp[k++] = arr[i++]; |
| 161 | + } else { |
| 162 | + tmp[k++] = arr[j++]; |
| 163 | + } |
| 164 | + } |
| 165 | + int start = i; |
| 166 | + int end = q; |
| 167 | + if (j <= right) { |
| 168 | + start = j; |
| 169 | + end = right; |
| 170 | + } |
| 171 | + while (start <= end) { |
| 172 | + tmp[k++] = arr[start++]; |
| 173 | + } |
| 174 | + for (int l = 0; l <= right - left; l++) { |
| 175 | + arr[l + left] = tmp[l]; |
| 176 | + } |
| 177 | + |
| 178 | + } |
| 179 | + |
| 180 | + /** |
| 181 | + * 快速排序 |
| 182 | + * |
| 183 | + * @param arr |
| 184 | + */ |
| 185 | + public static void quickSort(int[] arr, int left, int right) { |
| 186 | + if (left >= right) { |
| 187 | + return; |
| 188 | + } |
| 189 | + int q = partition2(arr, left, right); |
| 190 | + quickSort(arr, left, q - 1); |
| 191 | + quickSort(arr, q + 1, right); |
| 192 | + } |
| 193 | + |
| 194 | + private static int partition(int[] arr, int left, int right) { |
| 195 | + int pivot = arr[right]; |
| 196 | + int i = left; |
| 197 | + for (int j = left; j < right; j++) { |
| 198 | + if (arr[j] < pivot) { |
| 199 | + if (i == j) { |
| 200 | + ++i; |
| 201 | + } else { |
| 202 | + int tmp = arr[i]; |
| 203 | + arr[i++] = arr[j]; |
| 204 | + arr[j] = tmp; |
| 205 | + } |
| 206 | + } |
| 207 | + } |
| 208 | + int tmp = arr[i]; |
| 209 | + arr[i] = arr[right]; |
| 210 | + arr[right] = tmp; |
| 211 | + return i; |
| 212 | + } |
| 213 | + |
| 214 | + private static int partition2(int[] arr, int left, int right) { |
| 215 | + // 三数取中法 , 随机数在这里写 |
| 216 | + int middle = (left + right) / 2; |
| 217 | + int pivot = arr[middle]; |
| 218 | + // 交换到最右边 |
| 219 | + int val = arr[right]; |
| 220 | + arr[right] = pivot; |
| 221 | + arr[middle] = val; |
| 222 | + int i = left; |
| 223 | + for (int j = left; j < right; j++) { |
| 224 | + if (arr[j] < pivot) { |
| 225 | + if (i == j) { |
| 226 | + ++i; |
| 227 | + } else { |
| 228 | + int tmp = arr[i]; |
| 229 | + arr[i++] = arr[j]; |
| 230 | + arr[j] = tmp; |
| 231 | + } |
| 232 | + } |
| 233 | + } |
| 234 | + int tmp = arr[i]; |
| 235 | + arr[i] = arr[right]; |
| 236 | + arr[right] = tmp; |
| 237 | + return i; |
| 238 | + } |
| 239 | + |
| 240 | + /** |
| 241 | + * 三向切分快速排序 |
| 242 | + * |
| 243 | + * @param arr |
| 244 | + * @param left |
| 245 | + * @param right |
| 246 | + * @return |
| 247 | + */ |
| 248 | + private static void quickSort3(int[] arr, int left, int right) { |
| 249 | + if (left >= right) { |
| 250 | + return; |
| 251 | + } |
| 252 | + int l = left; |
| 253 | + int k = left + 1; |
| 254 | + int r = right; |
| 255 | + int pivot = arr[l]; |
| 256 | + |
| 257 | + while (k <= r) { |
| 258 | + if (arr[k] < pivot) { |
| 259 | + int tmp = arr[l]; |
| 260 | + arr[l] = arr[k]; |
| 261 | + arr[k] = tmp; |
| 262 | + l++; |
| 263 | + k++; |
| 264 | + } else if (arr[k] == pivot) { |
| 265 | + k++; |
| 266 | + } else { |
| 267 | + if (arr[r] > pivot) { |
| 268 | + r--; |
| 269 | + } else if (arr[r] == pivot) { |
| 270 | + int tmp = arr[k]; |
| 271 | + arr[k] = arr[r]; |
| 272 | + arr[r] = tmp; |
| 273 | + k++; |
| 274 | + r--; |
| 275 | + } else { |
| 276 | + int tmp = arr[l]; |
| 277 | + arr[l] = arr[r]; |
| 278 | + arr[r] = arr[k]; |
| 279 | + arr[k] = tmp; |
| 280 | + l++; |
| 281 | + k++; |
| 282 | + r--; |
| 283 | + } |
| 284 | + } |
| 285 | + } |
| 286 | + |
| 287 | + quickSort(arr, left, l - 1); |
| 288 | + quickSort(arr, r + 1, right); |
| 289 | + } |
| 290 | + |
| 291 | + /** |
| 292 | + * 双轴快速排序 |
| 293 | + * |
| 294 | + * @param arr |
| 295 | + * @param left |
| 296 | + * @param right |
| 297 | + */ |
| 298 | + private static void quickSort4(int[] arr, int left, int right) { |
| 299 | + if (left >= right) { |
| 300 | + return; |
| 301 | + } |
| 302 | + int l = left; |
| 303 | + int k = left + 1; |
| 304 | + int r = right; |
| 305 | + // 判断pivot1 与 pivot2 大小 |
| 306 | + if (arr[l] > arr[r]) { |
| 307 | + int tmp = arr[l]; |
| 308 | + arr[l] = arr[r]; |
| 309 | + arr[r] = tmp; |
| 310 | + } |
| 311 | + int pivot1 = arr[l]; |
| 312 | + int pivot2 = arr[r]; |
| 313 | + |
| 314 | + while (k < r) { |
| 315 | + if (arr[k] < pivot1) { |
| 316 | + l++; |
| 317 | + if (l != k) { |
| 318 | + int tmp = arr[l]; |
| 319 | + arr[l] = arr[k]; |
| 320 | + arr[k] = tmp; |
| 321 | + } |
| 322 | + k++; |
| 323 | + } else if (arr[k] >= pivot1 && arr[k] <= pivot2) { |
| 324 | + k++; |
| 325 | + } else { |
| 326 | + --r; |
| 327 | + if (arr[r] > pivot2) { |
| 328 | + } else if (arr[r] >= pivot1 && arr[r] <= pivot2) { |
| 329 | + int tmp = arr[k]; |
| 330 | + arr[k] = arr[r]; |
| 331 | + arr[r] = tmp; |
| 332 | + k++; |
| 333 | + } else { |
| 334 | + l++; |
| 335 | + int tmp = arr[l]; |
| 336 | + arr[l] = arr[r]; |
| 337 | + arr[r] = arr[k]; |
| 338 | + arr[k] = tmp; |
| 339 | + k++; |
| 340 | + } |
| 341 | + } |
| 342 | + } |
| 343 | + |
| 344 | + // 交换pivot1 和 pivot2 |
| 345 | + arr[left] = arr[l]; |
| 346 | + arr[l] = pivot1; |
| 347 | + arr[right] = arr[r]; |
| 348 | + arr[r] = pivot2; |
| 349 | + |
| 350 | + quickSort(arr, left, l - 1); |
| 351 | + quickSort(arr, l + 1, r - 1); |
| 352 | + quickSort(arr, r + 1, right); |
| 353 | + } |
| 354 | + |
| 355 | + /** |
| 356 | + * O(n) 时间复杂度内求无序数组中的第 K 大元素。比如, 4 , 2 , 5 , 12 , 3 这样一组数据,第 3 大元素就是 4 。 |
| 357 | + * |
| 358 | + * @param arr |
| 359 | + */ |
| 360 | + public static int sort(int[] arr, int l, int r, int k) { |
| 361 | + if (l >= r) { |
| 362 | + return 0; |
| 363 | + } |
| 364 | + int p = partition(arr, l, r); |
| 365 | + if ((p + 1) == k) { |
| 366 | + return arr[p]; |
| 367 | + } else if ((p + 1) < k) { |
| 368 | + return sort(arr, p + 1, r, k); |
| 369 | + } else { |
| 370 | + return sort(arr, l, p - 1, k); |
| 371 | + } |
| 372 | + } |
| 373 | + |
| 374 | + public static void main(String[] args) { |
| 375 | + int[] arr = {2, 1, 5, 6, 8, 4, 12, 11, 13, 15, 7, 9, 0, -1}; |
| 376 | +// bubbleSort(arr); |
| 377 | +// bubbleSort2(arr); |
| 378 | +// selectSort(arr); |
| 379 | +// mergeSort(arr, 0, arr.length - 1); |
| 380 | +// quickSort4(arr, 0, arr.length - 1); |
| 381 | + |
| 382 | + Arrays.sort(arr); |
| 383 | + print(arr); |
| 384 | + |
| 385 | + } |
| 386 | + |
| 387 | + public static void print(int[] arr) { |
| 388 | + for (int i : arr) { |
| 389 | + System.out.print(i + " "); |
| 390 | + } |
| 391 | + System.out.println(); |
| 392 | + } |
| 393 | + |
| 394 | + |
| 395 | +} |
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