Update vapid requirement

Author: jrconlin

README.md

@@ -169,4 +169,30 @@ Encode the `data` for future use. On error, returns a `WebPushException`
 encoded_data = WebPush(subscription_info).encode(data)
 ```
 
+## Stand Alone Webpush
+
+If you're not really into coding your own solution, there's also a "stand-alone" `pywebpush` command in the
+./bin directory.
+
+This uses two files:
+* the *data* file, which contains the message to send, in whatever form you like.
+* the *subscription info* file, which contains the subscription information as JSON encoded data. This is usually returned by the Push `subscribe` method and looks something like:
+
+```json
+{"endpoint": "https://push...",
+ "keys": {
+     "auth": "ab01...",
+     "p256dh": "aa02..."
+ }}
+```
+
+If you're interested in just testing your applications WebPush interface, you could use the Command Line:
+
+```bash
+./bin/pywebpush --data stuff_to_send.data --info subscription.info
+```
+which will encrypt and send the contents of `stuff_to_send.data`.
+
+See `./bin/pywebpush --help` for available commands and options.
+
 

requirements.txt

@@ -1,4 +1,4 @@
 cryptography>=2.6.1
 http-ece>=1.1.0
 requests>=2.21.0
-py-vapid>=1.4.0
+py-vapid>=1.5.0

setup.py

@@ -4,7 +4,7 @@
 from setuptools import find_packages, setup
 
 
-__version__ = "1.9.2"
+__version__ = "1.9.3"
 
 
 def read_from(file):