work: remove a statement with no effect

lyakh · nashif · commit d7a37529159a · 2021-05-07T12:44:34.000-04:00
work_timeout() is a function, a statement like "(void)work_timeout;"
has no effect.

Signed-off-by: Guennadi Liakhovetski &lt;guennadi.liakhovetski@linux.intel.com&gt;
diff --git a/kernel/work.c b/kernel/work.c
@@ -824,7 +824,6 @@ void k_work_init_delayable(struct k_work_delayable *dwork,
 		},
 	};
 	z_init_timeout(&dwork->timeout);
-	(void)work_timeout;
 }
 
 static inline int work_delayable_busy_get_locked(const struct k_work_delayable *dwork)

Original file line number	Diff line number	Diff line change
`@@ -824,7 +824,6 @@ void k_work_init_delayable(struct k_work_delayable *dwork,`
`824`	`824`	`},`
`825`	`825`	`};`
`826`	`826`	`z_init_timeout(&dwork->timeout);`
`827`		`- (void)work_timeout;`
`828`	`827`	`}`
`829`	`828`
`830`	`829`	`static inline int work_delayable_busy_get_locked(const struct k_work_delayable *dwork)`