fix: lua call error

Author: zeromake

.gitignore

@@ -1,25 +1,27 @@
-build
-.xmake
-.vscode/*.json
-.DS_Store
-.idea
-*.a
-*.o
-
-3rd/*
-!3rd/fetch.lua
-!3rd/copy.lua
-!3rd/xmake.lua
-!3rd/pre
-!3rd/.include
-!.vscode/launch.json
-dist
-.xrepo
-project.xcworkspace
-xcuserdata
-cmake_install.cmake
-CMakeCache.txt
-CMakeLists.txt
-*.xcodeproj
-CMakeFiles
-CMakeScripts
+build
+.xmake
+.vscode/*.json
+.DS_Store
+.idea
+*.a
+*.o
+
+3rd/*
+!3rd/fetch.lua
+!3rd/copy.lua
+!3rd/xmake.lua
+!3rd/pre
+!3rd/.include
+!.vscode/launch.json
+dist
+.xrepo
+project.xcworkspace
+xcuserdata
+cmake_install.cmake
+CMakeCache.txt
+CMakeLists.txt
+*.xcodeproj
+CMakeFiles
+CMakeScripts
+
+games

src/LUAHandler.cpp

@@ -1318,8 +1318,8 @@ int LUAHandler::callFunction(bool is_callback, const char *cmd, void *data) {
         buf = new char[strlen(p) + 1]{0};
         memcpy(buf, p, strlen(p) + 1);
         lua_pushstring(state, buf);
-    } else {
-        // 自动读取变量
+    } else if (false) {
+        // Todo 自动读取变量，之前有旧版实现已经是在 lua 再调用其他 lua 的 c 实现来读取参数不能默认开启，等加一个开关在 ns 脚本里手动开启
         sh->nextParam();
         while (sh->current_variable.type != ScriptHandler::VAR_NONE) {
             if (sh->current_variable.type == ScriptHandler::VAR_INT) {

xmake.lua

@@ -45,6 +45,7 @@ if is_plat("windows") then
     add_defines("XMD_H=1")
     add_cxflags("/utf-8")
     add_cxflags("/UNICODE")
+    add_cxflags("/EHsc")
 
     if get_config("omp") then
         add_cxflags("/openmp")