Memoize.js

// The Problem
// Create a memoize function that takes another function as an argument and 
// returns a new version of that function. If the new function is called with 
// inputs it has seen before, it should return the cached result instead of 
// recalculating it.

const val = new Map();

let arr = [1,2,3,1,3,4,2,1];
val.set(arr)

console.log(val)


function memoize(callback) {

    const cache = new Map();

    return function (...args) {

        const key = JSON.stringify(args);
        console.log(key);


        // if cache
        if (cache.has(key)) {
            console.log('Return from Cache')
            return key
        }


        const result = callback(...args);
        cache.set(key);
        console.log('Setting New Keys')

        console.log('entries => ', cache.entries())
        return result;
    }


}

function sum(a, b) {
    return a + b
}

const memoizedValue = memoize(sum);

console.log(memoizedValue(5, 10));
console.log(memoizedValue(5, 10));