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rotateimage.js
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57 lines (42 loc) · 1.39 KB
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/*
You are given an n x n 2D matrix representing an image, rotate the image by 90 degrees (clockwise).
You have to rotate the image in-place, which means you have to modify the input 2D matrix directly. DO NOT allocate another 2D matrix and do the rotation.
Example 1:
Input: matrix = [[1,2,3],[4,5,6],[7,8,9]]
Output: [[7,4,1],[8,5,2],[9,6,3]]
Example 2:
Input: matrix = [[5,1,9,11],[2,4,8,10],[13,3,6,7],[15,14,12,16]]
Output: [[15,13,2,5],[14,3,4,1],[12,6,8,9],[16,7,10,11]]
Example 3:
Input: matrix = [[1]]
Output: [[1]]
Example 4:
Input: matrix = [[1,2],[3,4]]
Output: [[3,1],[4,2]]
*/
/**
* @param {number[][]} matrix
* @return {void} Do not return anything, modify matrix in-place instead.
*/
var rotate = function (matrix) {
/*
ip: [[1,2,3],[4,5,6],[7,8,9]]
reverse array => [ [ 7, 8, 9 ], [ 4, 5, 6 ], [ 1, 2, 3 ] ]
bring all 0 index of each array to 1st array
bring all 1 index of each array to 2nd array
bring all 2 index of each array to 3rd array
op: [[7,4,1],[8,5,2],[9,6,3]]
*/
let op = []
let arrCpy = Array.from(matrix);
let arr = arrCpy.reverse()
for (let i = 0; i < arr.length; i++) {
let sbArr = [];
for (let j = 0; j < arr[i].length; j++) {
sbArr.push(arr[j][i])
}
op.push(sbArr);
matrix[i] = sbArr;
}
console.log("op ", op)
};