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查询需求:随机查询一个节点,然后使用path()单步返回与其一度关联的点和边 g.V().limit(1).optional(bothE().otherV()).path().limit(5)查询结果:可以返回预期的路径,但是返回结果中只有点和边的 |
Answered by
simon824
Feb 7, 2021
Replies: 1 comment
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可以试试看这条语句是否符合你的需求 |
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Answer selected by
mongooooo
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可以试试看这条语句是否符合你的需求