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Pull request overview
This pull request implements the isAnagram function in the 01-js easy exercises. The implementation uses a sorting approach to check if two strings are anagrams by converting them to lowercase, splitting them into character arrays, sorting, and comparing the results.
Changes:
- Implemented the
isAnagramfunction with case-insensitive string comparison using character sorting - Added detailed step-by-step comments explaining the algorithm
- Left commented-out original function stub in the file
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| function isAnagram(str1, str2) { | ||
| // Step 1: Make both strings lowercase | ||
| str1 = str1.toLowerCase(); | ||
| str2 = str2.toLowerCase(); | ||
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| // Step 2: Check if lengths match | ||
| if (str1.length !== str2.length) { | ||
| return false; // Different lengths mean not anagrams | ||
| } | ||
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| // Step 3: Sort the characters in each string | ||
| const sorted1 = str1.split('').sort().join(''); // Split to array, sort, join back | ||
| const sorted2 = str2.split('').sort().join(''); | ||
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| // Step 4: Compare sorted versions | ||
| return sorted1 === sorted2; // True if they match | ||
| } |
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The implementation doesn't handle whitespace correctly. According to the test cases, strings with spaces like 'rail safety' and 'fairy tales' should be considered anagrams, but the current implementation will fail because spaces are not filtered out before comparison. Consider removing all whitespace from both strings before sorting and comparing.
| // function isAnagram(str1, str2) { | ||
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| // } | ||
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| // module.exports = isAnagram; | ||
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| // solution | ||
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| function isAnagram(str1, str2) { | ||
| // Step 1: Make both strings lowercase | ||
| str1 = str1.toLowerCase(); | ||
| str2 = str2.toLowerCase(); | ||
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| // Step 2: Check if lengths match | ||
| if (str1.length !== str2.length) { | ||
| return false; // Different lengths mean not anagrams | ||
| } | ||
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| // Step 3: Sort the characters in each string | ||
| const sorted1 = str1.split('').sort().join(''); // Split to array, sort, join back | ||
| const sorted2 = str2.split('').sort().join(''); | ||
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Commented-out code and empty comment markers should be removed. Lines 7-11 contain the original function stub and module export that are now duplicated below, and line 14 has an empty "solution" comment. These should be cleaned up to improve code maintainability.
| // function isAnagram(str1, str2) { | |
| // } | |
| // module.exports = isAnagram; | |
| // solution | |
| function isAnagram(str1, str2) { | |
| // Step 1: Make both strings lowercase | |
| str1 = str1.toLowerCase(); | |
| str2 = str2.toLowerCase(); | |
| // Step 2: Check if lengths match | |
| if (str1.length !== str2.length) { | |
| return false; // Different lengths mean not anagrams | |
| } | |
| // Step 3: Sort the characters in each string | |
| const sorted1 = str1.split('').sort().join(''); // Split to array, sort, join back | |
| const sorted2 = str2.split('').sort().join(''); | |
| function isAnagram(str1, str2) { | |
| // Step 1: Make both strings lowercase | |
| str1 = str1.toLowerCase(); | |
| str2 = str2.toLowerCase(); | |
| // Step 2: Check if lengths match | |
| if (str1.length !== str2.length) { | |
| return false; // Different lengths mean not anagrams | |
| } | |
| // Step 3: Sort the characters in each string | |
| const sorted1 = str1.split('').sort().join(''); // Split to array, sort, join back | |
| const sorted2 = str2.split('').sort().join(''); |
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Excessive blank lines add no value and should be removed to improve code readability and maintainability.
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