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CheezItMan
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Nice recursive DFS solution. Well done!
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| # Time complexity: O(V + E), where V is the number of vertices and E is the number of adjecent neighbors. | ||
| # Space complexity: O(V) where v is the number of vertices/dogs because of the dog_group array. The recursive stack will be at most O(n), as well. | ||
| def possible_bipartition(dislikes) |
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