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Emily's Completed Methods for Arrays#34

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Emily's Completed Methods for Arrays#34
emirry wants to merge 1 commit intoAda-C14:masterfrom
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@emirry emirry commented Sep 22, 2020

*need to review Big-O!

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Well done Emily, take a look at my comments and let me know what questions you have. Nice work.

Comment on lines +9 to 11
# Time complexity: O(n) because I'm performing a linear search until the loop reaches nil in the array.
# Space complexity: O(1), because I'm only looking for 1 value, it doesn't matter what size the array is.
def length(array)
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👍

Comment on lines +21 to 23
# Time complexity: O(1) because retrieving an element is constant, regardless of the size.
# Space complexity: O(1) because size of the array doesn't matter? Still retrieving one element at a time.
def print_array(array)
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👍 , however the time complexity is O(n) because you print out n elements and it increases as the size of the array increases proportionately.

Comment on lines +33 to 35
# Time complexity: O(n) for an unsorted array, because of its linear search to find that value.
# Space complexity: O(1), because I'm only looking for 1 value.
def search(array, length, value_to_find)
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👍

Comment on lines +48 to 50
# Time complexity: O(n) because it involves a linear search for an unsorted array. O(1), if it's sorted because the search will end if it's the first element (largest_value = array[0]).
# Space complexity: O(1), because I'm only looking for 1 value.
def find_largest(array, length)
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👍

Comment on lines +65 to 67
# Time complexity: O(n) because it involves a linear search for an unsorted array. O(1), if it's sorted because the search will end if it's the first element (smallest_val = array[0]).
# Space complexity: O(1), because I'm only looking for 1 value.
def find_smallest(array, length)
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👍

Comment on lines +80 to 82
# Time complexity: O(1), because I'm retrieving one element at a time?
# Space complexity: O(1)
def reverse(array, length)
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👍 , however the time complexity is O(n) because you loop n/2 times.

Comment on lines +99 to 101
# Time complexity: O(log n), to narrow down my search by n/2 after an iteration, and then n/4 if there's another iteration that's needed to find the value.
# Space complexity: O(1), because I'm only looking for 1 value.
def binary_search(array, length, value_to_find)
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👍

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