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CheezItMan
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Apr 28, 2021
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Well done Ringo, you hit the learning goals. I had one comment on dequeue, but otherwise this works well.
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| Time Complexity: O(n), the function has to visit every node once | ||
| but operations performed in that loop are O(1) | ||
| Space Complexity: O(n), worst case scenario the stack could have on it | ||
| every character in the string | ||
| */ | ||
| const balanced = (str) => { |
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| Time Complexity: O(n), the function has to check every character in expr, | ||
| but operations in the for loop are O(1) | ||
| Space Complexity: O(n), the controlling factor is the height of the stack, | ||
| which does not grow quickly with longer expr in a normal use case but I suppose | ||
| in a worst case scenario with some weird postfix expressions would increase in size | ||
| linear to the length of the weird expression you were using | ||
| */ | ||
| const evaluatePostfix = (expr) => { |
| } | ||
| } | ||
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| dequeue() { |
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👍 Very compact! However what happens if you dequeue an empty queue?
| this.tail = 0; | ||
| } | ||
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| enqueue(element) { |
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