Cheetahs - Emma and Alyssa #70
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jbieniosek
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Oct 5, 2022
jbieniosek
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jbieniosek
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Great work on this project Emma and Alyssa! The code is very clean and easy to read. This project is green.
| @@ -1,11 +1,51 @@ | |||
| import random | |||
| from adagrams.const_dicts import * | |||
| pass | ||
| letter_pool_list = [] | ||
| for letter, number in LETTER_POOL.items(): | ||
| letter_pool_list.extend([letter]*number) |
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Great way to handle the distribution!
Comment on lines
+9
to
+11
| while len(hand_list) < 10: | ||
| random.shuffle(letter_pool_list) | ||
| hand_list.append(letter_pool_list.pop()) |
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This works well to generate a list of 10 random letters, but it's doing a lot of extra work. random.shuffle will randomize the list, and once it's randomized, selecting the first 10 letters will give you a random hand of letters. Reshuffling between each selection isn't necessary.
| pass | ||
| word = word.upper() | ||
| new_letter_bank = [] | ||
| new_letter_bank.extend(letter_bank) |
| new_letter_bank.extend(letter_bank) | ||
| for letter in word: | ||
| if letter in new_letter_bank: | ||
| new_letter_bank.remove(letter) |
| if len(word) >= 7: | ||
| sum += 8 | ||
| for letter in word: | ||
| sum += SCORE_CHART_DICT[letter] |
| if high_word_length == 10 and word_length < high_word_length or word_length == high_word_length: | ||
| continue | ||
| elif word_length < high_word_length or word_length == 10: | ||
| highest_score_word = word |
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