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Copy file name to clipboardExpand all lines: _posts/2021-09-07-design-of-the-koji-room-koji-muro.md
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@@ -114,6 +114,7 @@ This is a 1-dimensional heat transfer problem. If we pick 4-inch polyurethane wi
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If the indoor conditions are maintained at 30°C, we can further demonstrate that the heat losses through the wall will total **764W**. To keep the room warm, an equal amount of heat must be supplied. Let's illustrate the conditions of the koji room at time t=0 after inoculation, during which the koji generates no heat and all openings to the room are closed:
*Heat balance of the koji room immediately after inoculation*
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### 3. Ventilation
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*Heat balance of the koji room with ventilation sized for heat removal*
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Next, let's consider the requirements for **moisture removal**. About 80% of the heat generated by koji is lost as water vapour, with the remaining 20% lost due to other effects. At the peak of its heat generation, we can show that the our 300kg of koji will emit 2.16kg of water per hour (see Appendix - Step 5). By exchanging moist indoor air with dry, outdoor air, we can show that a ventilation rate of **119m³/h** is necessary to remove the moisture emitted by koji.
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*Mass balance of the koji room with ventilation sized for moisture removal*
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Finally, let's consider the requirements for **carbon dioxide removal**. Koji has a respiratory coefficient of around 1.0 throughout its entire process, which means that the koji's peak heat generation of 1623W equates to a CO₂ generation rate of 0.3m³ CO₂/h (see Appendix - Step 6) using the aerobic metabolism equation:
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If we maintain an indoor carbon dioxide concentration at 4500ppm, which is 500ppm below the OSHA Permissible Exposure Limit (PEL = 5000ppm), and assume an outdoor CO₂ concentration of 500ppm, we can show that the flow rate necessary to remove all generated carbon dioxide is **76m³/h.**
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*Mass balance of the koji room with ventilation sized for carbon dioxide removal*
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Comparing the three ventilation rates, we can see that **moisture removal**, at 119m³/h, is the limiting design criteria in our scenario.
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Knowing that our maximum ventilation rate will be **119m³/h**, let's size the heating panels of the koji-room. Our conductive heat losses are 764W, and ventilating fresh air at 119m³/h removes 2480W of heat. Our koji generates 1623W of heat at its peak, so our heater must provide at least 1621W of heat (see Appendix - Step 7):
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*Final heat balance the koji room with ventilation with ventilation sized for moisture removal*
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And that's it! At t=0h, our heaters will be running at 764W and our ventilation turned off; and at the peak of growth, our heaters will be running at 1459W and our ventilation at 119m³/h. This is our operating window, and every other point in time will fall somewhere between these two extremes. Achieving steady conditions is the job of whatever **control system** we select. This can range from a basic thermostat and humidistat to a programmable controller.
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@@ -241,7 +244,7 @@ And finally here's the best picture I could find of a koji room online, which is
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There are a lot more details difficult to cover in one post, but hopefully this will give you an idea of how to size, construct, and operate a koji room (*koji muro*), and even how to build some of the simpler koji-making machines.
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If you plan on constructing a koji room, or have constructed one already, I'd love to hear about it! Feel free to reach out to me on twitter @Keeifa
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If you plan on constructing a koji room, or have constructed one already, I'd love to hear about it! Feel free to reach out to me on twitter [@Keeifa](https://twitter.com/Keeifa)
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This post is part of an ongoing effort to translate Japanese koji-related literature to the west. If you're interested in this, feel free to reach out to me as well.
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Air flows in this post are using a dry air basis at 30°C / 70% RH (indoor conditions).
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#### Step 2 - Determine the koji amount, dry weight, and room dimensions.
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The weight of steamed rice at inoculation (hiki-komi) will be 300kg. If the unsoaked white rice has a moisture of 13%, and the water absorption ratio at inoculation is 34%, the actual water content of the koji is:
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Let the depth of koji be 5cm. Based on Table 1, 300kg of steamed rice will occupy approximately 660L or 0.66m³ in volume and require a table with an area of 13.2 square meters (geometric calculations not shown). Let's select a 5.3m x 2.5m table. To allow for clearance and the storage of other items, let's select a room of 8m (L) x 5m (W). Finally, a ceiling height of 2.0-2.2m is standard - we will select 2.2m (H).
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#### Step 3 - Determine heat loss through the room walls, and check for condensation
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1-D steady state heat transfer through a wall is given by the following equation:
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