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[YoungSeok-Choi] week 6 solutions #1409
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0d5b434
add: Valid Parentheses
Yongseok-Choi-dev b4b8026
add: 증가하는 최대 부분수열
Yongseok-Choi-dev ff8a468
add: 물담기
Yongseok-Choi-dev 98a55c0
add: 나선 배열
Yongseok-Choi-dev 69c9e82
Merge remote-tracking branch 'upstream/main' into feature/week-6
Yongseok-Choi-dev 51256af
add: prefix tire 개선
Yongseok-Choi-dev ae12971
add: 문자사전
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Original file line number | Diff line number | Diff line change |
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@@ -0,0 +1,33 @@ | ||
import java.util.Stack; | ||
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// TC: O(n) | ||
class Solution { | ||
Stack<Character> st = new Stack<>(); | ||
public boolean isValid(String s) { | ||
for(char c : s.toCharArray()) { | ||
if(st.empty() || !isClosing(c)) { | ||
st.push(c); | ||
continue; | ||
} | ||
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char temp = st.peek(); | ||
if(temp == '(' && c == ')') { | ||
st.pop(); | ||
} else if(temp == '[' && c == ']') { | ||
st.pop(); | ||
} else if(temp == '{' && c == '}') { | ||
st.pop(); | ||
} else { | ||
st.push(c); | ||
} | ||
} | ||
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return st.empty(); | ||
} | ||
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public boolean isClosing(char c) { | ||
if(c == ')' || c == ']' || c == '}') return true; | ||
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return false; | ||
} | ||
} |
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stack에 쌓아야 하는 조건들을 먼저 검사해서 for-loop 횟수를 최소화 하는 접근이 인상적이네요~~!