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38 changes: 38 additions & 0 deletions clone-graph/lhc0506.js
Original file line number Diff line number Diff line change
@@ -0,0 +1,38 @@
/**
* // Definition for a _Node.
* function _Node(val, neighbors) {
* this.val = val === undefined ? 0 : val;
* this.neighbors = neighbors === undefined ? [] : neighbors;
* };
*/

/**
* @param {_Node} node
* @return {_Node}
*/
var cloneGraph = function(node) {
if (!node) return null;

const stack = [node];
const map = new Map();

map.set(node.val, new _Node(node.val));

while (stack.length > 0) {
const currentNode = stack.pop();

for (const neighbor of currentNode.neighbors) {
if (!map.has(neighbor.val)) {
map.set(neighbor.val, new Node(neighbor.val));
stack.push(neighbor);
}
map.get(currentNode.val).neighbors.push(map.get(neighbor.val));
}

}
return map.get(node.val);
};


// 시간복잡도: O(n)
// 공간복잡도: O(n)
32 changes: 32 additions & 0 deletions longest-repeating-character-replacement/lhc0506.js
Original file line number Diff line number Diff line change
@@ -0,0 +1,32 @@
/**
* @param {string} s
* @param {number} k
* @return {number}
*/
var characterReplacement = function(s, k) {
let start = 0;
let maxFreq = 0;
let result = 0;
const map = new Map();

for (let end = 0; end < s.length; end++) {
const endChar = s[end];
map.set(endChar, 1 + (map.get(endChar) || 0));

maxFreq = Math.max(maxFreq, map.get(endChar));

if (end - start + 1 - maxFreq > k) {
const startChar = s[start];
map.set(startChar, map.get(startChar) - 1);
start++;

}

result = Math.max(result, end - start + 1);
}

return result;
};

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알파벳 대문자로만 입력값이 주어진다면 아래와 같이 배열을 쓰는 것도 하나의 방법일 것 같아요 :)

var characterReplacement = function(s, k) {
  const freq = new Array(26).fill(0);
  let start = 0;
  let maxFreq = 0;
  let result = 0;

  for (let end = 0; end < s.length; end++) {
      const index = s.charCodeAt(end) - 65;
      freq[index]++;
      maxFreq = Math.max(maxFreq, freq[index]);

      while (end - start + 1 - maxFreq > k) {
          freq[s.charCodeAt(start) - 65]--;
          start++;
      }

      result = Math.max(result, end - start + 1);
  }

  return result;
};

// 시간복잡도: O(n)
// 공간복잡도: O(1)
30 changes: 30 additions & 0 deletions palindromic-substrings/lhc0506.js
Original file line number Diff line number Diff line change
@@ -0,0 +1,30 @@
/**
* @param {string} s
* @return {number}
*/

var countSubstrings = function(s) {
let count = 0;
for (let i = 0; i < s.length; i++) {
let start = i;
let end = i;
while (start >= 0 && end < s.length && s[start] === s[end]) {
count += 1;
start -= 1;
end += 1;
}

start = i;
end = i + 1;
while (start >= 0 && end < s.length && s[start] === s[end]) {
count += 1;
start -= 1;
end += 1;
}
}

return count;
};

// 시간 복잡도: O(n^2)
// 공간 복잡도: O(1)
10 changes: 10 additions & 0 deletions reverse-bits/lhc0506.js
Original file line number Diff line number Diff line change
@@ -0,0 +1,10 @@
/**
* @param {number} n - a positive integer
* @return {number} - a positive integer
*/
var reverseBits = function(n) {
return parseInt(n.toString(2).padStart(32, '0').split('').reverse().join(''), 2);
};

// 시간복잡도: O(n)
// 공간복잡도: O(1)