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33 changes: 33 additions & 0 deletions binary-tree-level-order-traversal/eunhwa99.kt
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// https://leetcode.com/problems/binary-tree-level-order-traversal/description/
/**
* Example:
* var ti = TreeNode(5)
* var v = ti.`val`
* Definition for a binary tree node.
* class TreeNode(var `val`: Int) {
* var left: TreeNode? = null
* var right: TreeNode? = null
* }
*/
class Solution {
fun levelOrder(root: TreeNode?): List<List<Int>> {
val result = mutableListOf<List<Int>>()
if(root == null) return result

val queue: ArrayDeque<TreeNode> = ArrayDeque()
queue.add(root)

while (queue.isNotEmpty()) {
val levelSize = queue.size
val level = mutableListOf<Int>()
repeat(levelSize) {
val node = queue.removeFirst()
level.add(node.`val`)
node.left?.let { queue.add(it) }
node.right?.let { queue.add(it) }
}
result.add(level)
}
return result
}
}
19 changes: 19 additions & 0 deletions house-robber-ii/eunhwa99.kt
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// https://leetcode.com/problems/house-robber-ii/description/
class Solution {
fun rob(nums: IntArray): Int {
if (nums.size == 1) return nums[0]
return maxOf(rob(nums, 0, nums.size - 2), rob(nums, 1, nums.size - 1))
}

private fun rob(nums: IntArray, start: Int, end: Int): Int {
val dp = IntArray(nums.size) { 0 }
dp[start] = nums[start]
dp[start + 1] = maxOf(nums[start], nums[start + 1])
for (i in start + 2..end) {
dp[i] = maxOf(dp[i - 1], dp[i - 2] + nums[i])
}
return dp[end]
}
}
// TC: O(n)
// SC: O(n)