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18 changes: 18 additions & 0 deletions contains-duplicate/jun0811.js
Original file line number Diff line number Diff line change
@@ -0,0 +1,18 @@
/**
* @param {number[]} nums
* @return {boolean}
*/
var containsDuplicate = function (nums) {
const count = [];
let res = false;

for (const num of nums) {
if (count[num]) {
res = true;
break;
} else {
count[num] = 1;
}
}
return res;
};
29 changes: 29 additions & 0 deletions longest-common-subsequence/jun0811.js
Original file line number Diff line number Diff line change
@@ -0,0 +1,29 @@
/**
* @param {number[]} nums
* @return {number}
*/
var longestConsecutive = function (nums) {
const set = new Set();

// set 생성 : O(n)
for (const num of nums) {
set.add(num);
}

let res = 0;

// set 순회 : O(n)
for (const num of set) {
if (set.has(num - 1)) continue;
let tmp = 1;
let cur = num;
// While 루프 전체: O(n)
while (true) {
const v = (cur += 1);
if (set.has(v)) tmp += 1;
else break;
}
if (tmp > res) res = tmp;
}
return res;
};
12 changes: 12 additions & 0 deletions number-of-1-bits/jun0811.js
Original file line number Diff line number Diff line change
@@ -0,0 +1,12 @@
/**
* @param {number} n
* @return {number}
*/
var hammingWeight = function (n) {
let res = 0;
while (n > 0) {
res += n & 1;
n = n >> 1; // 나누기 2
}
return res;
};
20 changes: 20 additions & 0 deletions top-k-frequent-elements/jun0811.js
Original file line number Diff line number Diff line change
@@ -0,0 +1,20 @@
/**
* @param {number[]} nums
* @param {number} k
* @return {number[]}
*/
var topKFrequent = function (nums, k) {
const countMap = new Map();
for (const num of nums) {
if (countMap.has(num)) {
countMap.set(num, countMap.get(num) + 1);
} else {
countMap.set(num, 1);
}
}
const countArr = [...countMap];
countArr.sort((a, b) => b[1] - a[1]);

const res = countArr.slice(0, k).map((count) => count[0]);
return res;
};
26 changes: 26 additions & 0 deletions two-sum/jun0811.js
Original file line number Diff line number Diff line change
@@ -0,0 +1,26 @@
// Time Complexity : O(N^2)

var twoSum = function (nums, target) {
const l = nums.length;
for (let i = 0; i < l; i++) {
for (let j = i + 1; j < l; j++) {
const value = nums[i] + nums[j];
if (value == target) return [i, j];
}
}
};

// Time Complexity : O(N)

var twoSum = function (nums, target) {
const Map = {};

nums.forEach((num, idx) => {
Map[num] = idx;
});

for (const idx in nums) {
const value = target - nums[idx];
if (Map[value] >= 0 && Map[value] != idx) return [+idx, Map[value]];
}
};