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[hj4645] WEEK 01 solutions #1688
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0dab597
Solve: contains duplicate
hj4645 f310a52
add 개행문자
hj4645 1e37b25
Solve: two-sum
hj4645 2efa74a
chore: 개행문자 수정
hj4645 0f90967
Solve: top-k-frequent-elements
hj4645 36449d2
Solve : longest-consecutive-sequence, house-robber
hj4645 1ee09cc
resolve lint errors
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Original file line number | Diff line number | Diff line change |
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class Solution: | ||
# nums 에서 가장 빈도가 높은 k개의 요소를 찾는 문제 | ||
# 딕셔너리와 정렬을 사용해 해결 | ||
# 시간복잡도: O(n log n), 공간복잡도: O(n) | ||
def topKFrequent(self, nums: List[int], k: int) -> List[int]: | ||
freq_map = {} | ||
for num in nums: | ||
freq_map[num] = freq_map.get(num, 0) + 1 | ||
|
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sorted_nums = sorted(freq_map.items(), key=lambda x:x[1], reverse=True) | ||
return [num for num, _ in sorted_nums[:k]] | ||
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heapq나 bucket sort를 쓰면 O(n) 또는 O(n log k)로 더 빠르게 가능합니다. 물론 가독성과 정확성으로는 이 방법이 가장 좋아보이긴 합니다.