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[chrisjune] week 01 solutions #1708
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Original file line number | Diff line number | Diff line change |
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class Solution: | ||
def containsDuplicate(self, nums) -> bool: | ||
dic = {} | ||
for num in nums: | ||
dic[num] = dic.get(num, 0) + 1 | ||
for v in dic.values(): | ||
if v > 1: | ||
return True | ||
return False |
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Original file line number | Diff line number | Diff line change |
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@@ -0,0 +1,12 @@ | ||
from typing import List | ||
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class Solution: | ||
def rob(self, nums: List[int]) -> int: | ||
if len(nums) <= 1: | ||
return nums[0] | ||
dp = [0] * len(nums) | ||
dp[0], dp[1] = nums[0], max(nums[0], nums[1]) | ||
for i in range(2, len(nums)): | ||
dp[i] = max(dp[i - 1], nums[i] + dp[i - 2]) | ||
return dp[-1] |
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Original file line number | Diff line number | Diff line change |
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@@ -0,0 +1,18 @@ | ||
from typing import List | ||
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class Solution: | ||
def longestConsecutive(self, nums: List[int]) -> int: | ||
if len(nums) < 1: | ||
return 0 | ||
nums = list(set(nums)) | ||
nums.sort() | ||
dp = [0] * len(nums) | ||
dp[0] = 1 | ||
for i in range(1, len(nums)): | ||
if nums[i - 1] + 1 == nums[i]: | ||
dp[i] = dp[i - 1] + 1 | ||
else: | ||
dp[i] = 1 | ||
print(dp) | ||
return max(dp) |
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Original file line number | Diff line number | Diff line change |
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from typing import List | ||
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class Solution: | ||
def topKFrequent(self, nums: List[int], k: int) -> List[int]: | ||
dic = {} | ||
for num in nums: | ||
dic[num] = dic.get(num, 0) + 1 | ||
l = [(k, v) for k, v in dic.items()] | ||
l.sort(reverse=True, key=lambda x: x[1]) | ||
l = [i for i, _ in l] | ||
return l[:k] |
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Original file line number | Diff line number | Diff line change |
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@@ -0,0 +1,11 @@ | ||
from typing import List | ||
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class Solution: | ||
def twoSum(self, nums: List[int], target: int) -> List[int]: | ||
for i in range(len(nums)): | ||
for j in range(len(nums)): | ||
if i == j: | ||
continue | ||
if nums[i] + nums[j] == target: | ||
return [i, j] |
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저도 처음에 이중 for문으로 풀었었는데, 파이썬의 경우 dictionary를 사용하면 시간복잡도를 줄일 수 있는 방법으로도 풀 수 있을 거 같습니다!
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리뷰 감사합니다. 의견주신 dictionary로 풀었더니 속도개선이 잘 되었습니다
