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[hi-rachel] WEEK 04 Solutions #1816
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Original file line number | Diff line number | Diff line change |
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@@ -0,0 +1,57 @@ | ||
/** | ||
* Definition for singly-linked list. | ||
* function ListNode(val, next) { | ||
* this.val = (val===undefined ? 0 : val) | ||
* this.next = (next===undefined ? null : next) | ||
* } | ||
*/ | ||
/** | ||
* @param {ListNode} list1 | ||
* @param {ListNode} list2 | ||
* @return {ListNode} | ||
*/ | ||
|
||
/** | ||
* 반복 풀이 | ||
* | ||
* TC: O(n + m) | ||
* SC: O(1) | ||
*/ | ||
var mergeTwoLists = function (list1, list2) { | ||
const dummy = new ListNode(); // 결과 리스트의 시작을 고정할 가짜 헤드 | ||
let tail = dummy; // 결과의 꼬리를 가리키는 포인터 | ||
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// 두 리스트가 모두 남아있는 동안, 더 작은 노드를 tail 뒤에 붙인다 | ||
while (list1 !== null && list2 !== null) { | ||
if (list1.val <= list2.val) { | ||
tail.next = list1; | ||
list1 = list1.next; | ||
} else { | ||
tail.next = list2; | ||
list2 = list2.next; | ||
} | ||
tail = tail.next; | ||
} | ||
tail.next = list1 !== null ? list1 : list2; | ||
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||
return dummy.next; | ||
}; | ||
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/** | ||
* 재귀 풀이 | ||
* | ||
* TC: O(n + m) | ||
* SC: O(n + m) | ||
*/ | ||
var mergeTwoLists = function (list1, list2) { | ||
if (!list1) return list2; | ||
if (!list2) return list1; | ||
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||
if (list1.val <= list2.val) { | ||
list1.next = mergeTwoLists(list1.next, list2); | ||
return list1; | ||
} else { | ||
list2.next = mergeTwoLists(list1, list2.next); | ||
return list2; | ||
} | ||
}; |
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재귀로도 풀 수 있는 문제군요! 다양항 풀이 남겨주셔서 감사합니다.
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@hyer0705 리뷰 감사합니다. 승인 부탁드립니다.