[std-freejia] Week11 solutions#1933
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std-freejia merged 3 commits intoDaleStudy:mainfrom Oct 4, 2025
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@TonyKim9401 안녕하세요! 혹시 리뷰 부탁드려도 될까요? 감사합니다! |
wozlsla
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Oct 4, 2025
| public int missingNumber(int[] nums) { | ||
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| int totalSum = 0; | ||
| // 0부터 nums.length 까지 전부 합 |
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저도 풀면서 알았는데 전체 합을 구하는 공식도 n*(n+1)//2 있습니다. 이 경우 순회할 필요가 없으니 더 효율적일 수 있어요.
이번주도 수고하셨습니다!
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아! ㅎㅎ 그렇군요 공유 감사해요. 댓글도 감사합니다. 연휴 잘 보내세요!
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