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[Jeehay Park(박지혜)] Week 1 #640
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f56e213
contains-duplicate solution
Jeehay28 4a49e74
valid-palindrome solution
Jeehay28 15c9c08
top-k-frequent-elements solution
Jeehay28 2e0a8fe
longest-consecutive-sequence solution
Jeehay28 45a049d
Add valid-anagram solution
Jeehay28 92dd605
Revert "Add valid-anagram solution"
Jeehay28 f5ef578
Add house-robber solution
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Original file line number | Diff line number | Diff line change |
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@@ -0,0 +1,7 @@ | ||
/** | ||
* @param {number[]} nums | ||
* @return {boolean} | ||
*/ | ||
var containsDuplicate = function (nums) { | ||
return nums.length !== new Set(nums).size; | ||
}; |
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Original file line number | Diff line number | Diff line change |
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@@ -0,0 +1,25 @@ | ||
/** | ||
* @param {number[]} nums | ||
* @param {number} k | ||
* @return {number[]} | ||
*/ | ||
var topKFrequent = function (nums, k) { | ||
let result = []; | ||
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const obj = nums.reduce((acc, cur) => { | ||
acc[cur] = (acc[cur] || 0) + 1; | ||
return acc; | ||
}, {}); | ||
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const frequentValues = Object.values(obj) | ||
.sort((a, b) => b - a) | ||
.slice(0, k); | ||
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for (const [key, value] of Object.entries(obj)) { | ||
if (frequentValues.includes(value)) { | ||
result.push(parseInt(key)); | ||
} | ||
} | ||
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return result; | ||
}; |
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@@ -0,0 +1,17 @@ | ||
/** | ||
* @param {string} s | ||
* @return {boolean} | ||
*/ | ||
var isPalindrome = function (s) { | ||
const reg = /[a-z0-9]/g; | ||
const converted = s.toLowerCase().match(reg); | ||
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if (converted === null) { | ||
return true; | ||
} else { | ||
const forward = converted.join(""); | ||
const backward = converted.reverse().join(""); | ||
|
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return forward === backward; | ||
} | ||
}; |
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upper case도 정규식에 포함하면 논리의 흐름이 더 좋을 것 같습니다.
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리뷰 감사합니당~