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KwonNayeon
reviewed
Feb 3, 2025
KwonNayeon
approved these changes
Feb 7, 2025
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| if (nums.at(mid - 1) > nums.at(mid)) { | ||
| return nums[mid]; | ||
| } | ||
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| if (nums.at(mid + 1) < nums.at(mid)) { | ||
| return nums[mid + 1]; | ||
| } |
Contributor
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mid 값의 경계에 대한 조건을 없애면 코드를 더 단순화할 수 있을 것 같습니다!
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| // case 1 | ||
| cases.push(nums[i - 1]); | ||
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| // case 2 | ||
| cases.push(nums[i - 1] * products[i - 1][0]); | ||
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| // case 3 | ||
| cases.push(nums[i - 1] * products[i - 1][1]); |
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주석으로 케이스를 구분해주셔서 코드를 읽기 쉬웠습니다! 이번 주도 고생하셨습니다 😊
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