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content/杂七杂八/数学/解桂林四日游设计最优旅游路线的整数规划.md

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@@ -37,3 +37,109 @@ $X$ 需要满足以下约束:
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$$max\ S=\sum_{i,j}^{2,8}x_{ij}*A_{i 2}$$
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代码:
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```python
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import pulp as lp
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import numpy as np
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# ===================== 工具函数 ====================
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NAME_DICT = {
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0: "象鼻山", 1: "漓江", 2: "阳朔西街", 3: "遇龙河", 4: "十里画廊",
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5: "银子岩", 6: "龙脊梯田", 7: "靖江王城", 8: "两江四湖"
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}
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def idx_to_name(idx):
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return NAME_DICT[idx]
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# ===================== 导入数据 ====================
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NUM_DAYS = 3
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A = [
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[1.5, 60, 8],
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[4.5, 250, 10],
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[2, 0, 7],
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[2, 180, 9],
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[3, 40, 8],
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[2, 80, 7],
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[8, 100, 9],
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[2.5, 120, 6],
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[1.5, 180, 8],
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]
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A = np.asarray(A)
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NUM_POINTS = A.shape[0]
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print(A)
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print(f'共有{NUM_POINTS}个景点, 需要游玩{NUM_DAYS}')
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# ===================== 建模 ====================
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prob = lp.LpProblem("GuilinTravelOptProb", lp.LpMaximize)
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X = {}
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for i in range(NUM_DAYS):
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for j in range(NUM_POINTS):
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X[(i, j)] = lp.LpVariable(f'x_{i}_{j}', 0, 1, lp.LpBinary)
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## 添加目标
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prob += lp.lpSum([X[(i, j)] * A[j][2] for i in range(NUM_DAYS) for j in range(NUM_POINTS)]), "total s"
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## 添加约束
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# 次数约束
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for j in range(NUM_POINTS):
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prob += lp.lpSum([X[(i, j)] for i in range(NUM_DAYS)]) <= 1
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# 时间约束
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for i in range(NUM_DAYS):
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prob += lp.lpSum([X[(i, j)] * A[j][0] for j in range(NUM_POINTS)]) <= 10
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# 费用约束
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prob += lp.lpSum([X[(i, j)] * A[j][1] for i in range(NUM_DAYS) for j in range(NUM_POINTS)]) <= 800
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# 地理约束
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for i in range(NUM_DAYS):
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prob += lp.lpSum([X[(i, j)] for j in range(NUM_POINTS)]) <= 1 + NUM_POINTS * (1 - X[(i, 6)])
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for i in range(NUM_DAYS):
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prob += lp.lpSum([X[(i, j)] for j in range(2, 6)]) >= X[(i, 1)]
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prob += lp.lpSum([X[(i, 0)]]) <= 1 - X[(i, 1)]
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prob += lp.lpSum([X[(i, 7)]]) <= 1 - X[(i, 1)]
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# ===================== 求解 ====================
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prob.solve(lp.PULP_CBC_CMD(msg=False)) # 用编译的 cbc 求解器
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print("== 求解结果 ==")
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print(f"求解状态:{lp.LpStatus[prob.status]}")
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print(f"最大总兴趣度:{lp.value(prob.objective):.0f}")
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# 统计总数据
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total_cost = 0
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total_time = 0
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total_s = 0
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# 输出每天行程
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for i in range(NUM_DAYS):
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selected_j = [j for j in range(NUM_POINTS) if X[(i, j)].varValue == 1]
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selected_names = [idx_to_name(j) for j in selected_j]
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# 计算当天费用
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day_cost = sum([A[j][1] for j in selected_j])
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total_cost += day_cost
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total_time += sum([A[j][0] for j in selected_j])
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total_s += sum([A[j][2] for j in selected_j])
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# 计算当天游玩时间
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day_time = sum([A[j][0] for j in selected_j])
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print(f"\n{i + 1}天:")
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print(f" 游玩景点:{selected_names}")
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print(f" 游玩时间:{day_time}小时 | 当天费用:{day_cost}元 | 兴趣度: {total_s}")
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print(f"总用时:{total_time} 小时 | 总费用:{total_cost}元 | 总兴趣度:{total_s}")
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```
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