Issue #7 Correction / If SHUTDOWN (WAKE pin) feature is not needed, the pin can be leave unconnected Issue #9 #8
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If SHUTDOWN (WAKE pin) feature is not needed, the pin can be leave unconnected |
rtek1000
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rtek1000
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Skallwar
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Feb 29, 2024
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Skallwar
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Skallwar
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Thanks for you PR 🔥
I can't test it currently so I trust you on this :D
I will try to make a release out of it and if it break something for someone, the old version will still be there just in case
| uint8_t TIMER[4] = {20, 5, 5, 20}; | ||
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| Wire.beginTransmission(I2CADDR); | ||
| uint8_t _data[1]; |
Owner
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Instead of an array of 1, just make it an uint8_t
| for (i = 0; i < 4; ++i) { | ||
| Wire.write(REG[i]); | ||
| Wire.write(DATA[i]); | ||
| delay(TIMER[i]); |
Owner
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No need for a delay here? I don't have the hardware anymore but I remember spending a lot of time figuring out the timings, it wouldn't work otherwise
| uint8_t TIMER[2] = {20, 10}; | ||
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| Wire.beginTransmission(I2CADDR); | ||
| uint8_t _data[1]; |
| for (i = 0; i < 2; ++i) { | ||
| Wire.write(REG[i]); | ||
| Wire.write(DATA[i]); | ||
| delay(TIMER[i]); |
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| if(n == 5) { | ||
| SERIAL_ERROR.println("i2c write error: timeout"); | ||
| } else { | ||
| SERIAL_ERROR.print("i2c write error: "); | ||
| SERIAL_ERROR.print(n); | ||
| SERIAL_ERROR.print(" "); | ||
| SERIAL_ERROR.println(DATA_REG, HEX); | ||
| } |
Owner
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This block of code is in 2 places, could you make a function out of it?
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| [Tested with ESP32 DEV KIT V1] | ||
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Suggested change
| [Tested with ESP32 DEV KIT V1] | |
| ## Test hardware | |
| - Arduino Mega 2560 Rev3 | |
| - ESP32 DEV KIT V1 | |
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#7