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77 changes: 77 additions & 0 deletions bit_manipulation/count_distinct_primes_from_binary_string.cpp
Original file line number Diff line number Diff line change
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/**
* @file count_distinct_primes_from_binary_string.cpp
* @brief Count distinct primes formed from binary strings using allowed operations.
*
* @author Rudraksh Tank
* @date July 2025
*
* @details
* Given a binary string, the task is to count how many distinct prime decimal numbers
* can be formed by:
* - Swapping any two characters (makes position irrelevant)
* - Changing any '1' to '0' (not the reverse)
*
* Efficient solution using bit manipulation and Sieve of Eratosthenes.
*
* Tags: Bit Manipulation, Prime Numbers, Combinatorics, Greedy, Bitmask
*/

#include <iostream>
#include <vector>
#include <unordered_set>
#include <algorithm>

const int MAX = 1e6;
std::vector<bool> is_prime;

/**
* @brief Precomputes prime numbers up to MAX using the Sieve of Eratosthenes.
*/
void precomputePrimes() {
is_prime.assign(MAX + 1, true);
is_prime[0] = is_prime[1] = false;
for (int i = 2; i * i <= MAX; i++) {
if (is_prime[i]) {
for (int j = i * i; j <= MAX; j += i) {
is_prime[j] = false;
}
}
}
}

/**
* @brief Counts distinct prime numbers that can be formed from the given binary string.
* @param s Binary string input
* @return Number of distinct primes possible after allowed transformations
*/
int countPrimeBinaryStrings(const std::string &s) {
int n = s.length();
int k = std::count(s.begin(), s.end(), '1');
int cnt = 0;
int limit = 1 << n;

std::unordered_set<int> seen;

for (int i = 2; i < limit; i++) {
if (__builtin_popcount(i) <= k && is_prime[i]) {
if (!seen.count(i)) {
cnt++;
seen.insert(i);
}
}
}

return cnt;
}

/**
* @brief Main function to test the algorithm.
*/
int main() {
precomputePrimes();
std::string s;
std::cin >> s;
std::cout << countPrimeBinaryStrings(s) << std::endl;
return 0;
}