Create Maximum and minimum of an array using minimum number of comparisons

data_structures/arrays/Maximum and minimum of an array using minimum number of comparisons.py

@@ -0,0 +1,33 @@
+def find_min_max(arr):
+    if len(arr) == 0:
+        return None, None
+
+    if len(arr) == 1:
+        return arr, arr
+
+    if arr > arr:
+        max_val = arr
+        min_val = arr
+    else:
+        max_val = arr
+        min_val = arr
+
+    for i in range(2, len(arr) - 1, 2):
+        if arr[i] > arr[i + 1]:
+            max_val = max(max_val, arr[i])
+            min_val = min(min_val, arr[i + 1])
+        else:
+            max_val = max(max_val, arr[i + 1])
+            min_val = min(min_val, arr[i])
+
+    if len(arr) % 2 != 0:
+        max_val = max(max_val, arr[-1])
+        min_val = min(min_val, arr[-1])
+
+    return min_val, max_val
+
+
+# Example usage:
+arr = [3, 5, 1, 2, 4, 8]
+min_val, max_val = find_min_max(arr)
+print(f"Minimum value: {min_val}, Maximum value: {max_val}")