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68 changes: 68 additions & 0 deletions data_structures/arrays/new_combination.py
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from itertools import combinations


def permute_recursive(nums: list[int]) -> list[list[int]]:
"""
Return all permutations.

>>> permute_recursive([1, 2, 3])
[[3, 2, 1], [2, 3, 1], [1, 3, 2], [3, 1, 2], [2, 1, 3], [1, 2, 3]]
"""
result: list[list[int]] = []
if len(nums) == 0:
return [[]]
for _ in range(len(nums)):
n = nums.pop(0)
permutations = permute_recursive(nums.copy())
for perm in permutations:
perm.append(n)
result.extend(permutations)
nums.append(n)
return result


def permute_backtrack(nums: list[int]) -> list[list[int]]:
"""
Return all permutations of the given list.

>>> permute_backtrack([1, 2, 3])
[[1, 2, 3], [1, 3, 2], [2, 1, 3], [2, 3, 1], [3, 2, 1], [3, 1, 2]]
"""

def backtrack(start: int) -> None:
if start == len(nums) - 1:
output.append(nums[:])
else:
for i in range(start, len(nums)):
nums[start], nums[i] = nums[i], nums[start]
backtrack(start + 1)
nums[start], nums[i] = nums[i], nums[start] # backtrack

output: list[list[int]] = []
backtrack(0)
return output


def get_combinations(nums: list[int], r: int) -> list[list[int]]:
"""
Return all combinations of the given list of length r.

>>> get_combinations([1, 2, 3], 2)
[[1, 2], [1, 3], [2, 3]]
"""
return [list(comb) for comb in combinations(nums, r)]


if __name__ == "__main__":
import doctest

# Test permutations
result_permute = permute_backtrack([1, 2, 3])
print("Permutations:", result_permute)

# Test combinations
result_combinations = get_combinations([1, 2, 3], 2)
print("Combinations of length 2:", result_combinations)

# Run doctests
doctest.testmod()
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