[Python] Challenge 6 (Unreviewed)

challenge_4/python/whiterd/README.md

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+# Invert Binary Tree
+
+* Take in a binary tree object.
+
+* For each level in the tree, reverse the order of the items in that level (mirror).
+
+* Return the node object.

challenge_4/python/whiterd/src/invert_bin.py

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+#!/usr/bin/env python
+
+'''
+    Input:  An object consisting of a binary tree.
+
+    Output:  The same tree with values mirrored.
+'''
+
+def mirror(node):
+    if node:
+        mirror(node.left)
+        mirror(node.right)
+        node.left, node.right = node.right, node.left
+
+    return node

challenge_6/python/whiterd/README.md

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+# Range Finder-er :tm:
+###### Tested using Python 3.5.2 -- run using ```$ python src/id_ranges.py```
+
+### Purpose:
+
+* Identify the ranges that exist for a given input.
+
+### Assuptions:
+
+* Input is a non-empty list of ordered integers.
+
+### Example 1:
+
+Launch scipt and input a sequence of numbers separated by commas.
+
+```
+>>> Input a list of integers: [1,2,3,4,8,9,10,12,13,14]
+['1->4', '8->10', '12->14']
+```
+
+### Example 2:
+
+Given the input [1,2,3,4,9,10,15], your output should be:
+
+```
+>>> Input a list of integers: [1,2,3,4,9,10,15]
+['1->4', '9->10']
+```
+
+

challenge_6/python/whiterd/src/id_ranges.py

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+#!/usr/bin/env python
+
+"""
+    Identify the ranges that exist for a given input.
+
+    Assume: input is a non-empty list of ordered integers.
+"""
+from __future__ import print_function
+
+def range_finderer(new_list):
+    result = []
+    temp = []
+    for i in new_list:
+        if not temp:
+            temp.append(i)
+            continue
+        elif(i - 1 == temp[-1]):
+            temp.append(i)
+            continue
+        else:
+            result.append(str(temp[0]) + '->' + str(temp[-1]))
+            temp = [i]
+    result.append(str(temp[0]) + '->' + str(temp[-1]))
+    return result
+
+
+if __name__ == '__main__':
+
+    x = [int(x) for x in input('Input a list of integers: ')[1:-1].split(',')]
+    print(range_finderer(x))