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45 changes: 45 additions & 0 deletions Dynamic_Programming/Regular_Expression_Matching.cpp
Original file line number Diff line number Diff line change
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//Given a string s and a pattern p, implement regular expression matching with support for '.' (matches any single character) and '*' (zero or more of the preceding element).
//Example:

//Input: s = "mississippi", p = "mis*is*p*."
//Output: false

#include <iostream>
#include <vector>

using namespace std;

bool isMatch(string s, string p) {
int m = s.size();
int n = p.size();
vector<vector<bool>> dp(m + 1, vector<bool>(n + 1, false));
dp[0][0] = true;

// Fill the first row
for (int j = 1; j <= n; ++j) {
if (p[j - 1] == '*') {
dp[0][j] = dp[0][j - 2];
}
}

// Fill the dp array using dynamic programming
for (int i = 1; i <= m; ++i) {
for (int j = 1; j <= n; ++j) {
if (p[j - 1] == s[i - 1] || p[j - 1] == '.') {
dp[i][j] = dp[i - 1][j - 1];
} else if (p[j - 1] == '*') {
dp[i][j] = dp[i][j - 2] || (dp[i - 1][j] && (s[i - 1] == p[j - 2] || p[j - 2] == '.'));
}
}
}

return dp[m][n];
}

int main() {
string s = "mississippi";
string p = "mis*is*p*.";
bool result = isMatch(s, p);
cout << "Matching result: " << (result ? "true" : "false") << endl;
return 0;
}