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Update main.py #10
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Update main.py #10
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Summary of Changes
Hello @arvi18, I'm Gemini Code Assist1! I'm currently reviewing this pull request and will post my feedback shortly. In the meantime, here's a summary to help you and other reviewers quickly get up to speed!
This pull request refactors the main.py file by consolidating the Fibonacci number calculation logic. It removes redundant and less efficient implementations, standardizing on a memoized recursive approach for calculating the nth Fibonacci number. This change simplifies the codebase and ensures that the most efficient recursive method is used.
Highlights
- Fibonacci Implementation Consolidation: Removed two separate nth_fibonacci functions (one simple recursive, one dynamic programming) to streamline the codebase.
- Memoization Standardized: The primary nth_fibonacci function now consistently uses a memoized recursive approach via nth_fibonacci_util for efficient calculation.
- Code Cleanup: Unnecessary code blocks related to alternative Fibonacci implementations have been removed, improving readability and maintainability.
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🤖 Refacto.AI: PR Summary & Reviewer Guide🎯 1. The Goal (Why was this PR raised?)This PR aims to simplify the Fibonacci number calculation implementation in main.py by removing duplicate implementations and keeping only the memoization approach. 🗺️ 2. The Changes (What was implemented?)This section provides a walkthrough of the changes, connecting them to the PR's goals.
🤔 3. Key Areas for Human ReviewHere are the most important areas to focus your review on, including specific testing instructions. Area of Concern: Algorithm Implementation Removal
Area of Concern: Code Organization
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/refacto-test |
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Code Review
This pull request refactors the main.py file by removing two alternative implementations of the Fibonacci sequence calculation, consolidating on a single, memoized recursive approach. This is a positive change for code clarity and maintainability. However, the review has identified a potential regression in how invalid inputs are handled. The remaining implementation produces incorrect results for negative numbers, whereas one of the removed implementations would fail explicitly. It is recommended to add input validation to the nth_fibonacci function to address this.
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Refacto is reviewing this PR. Please wait for the review comments to be posted. |
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/refacto-test |
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Refacto is reviewing this PR. Please wait for the review comments to be posted. |
Multi-Domain Review: Fibonacci Implementation👍 Well Done
📌 Files Processed
📝 Additional Comments
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| # Function to calculate the nth Fibonacci number using memoization |
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Redundant Function Definition
The PR removes an inefficient recursive Fibonacci implementation without memoization. This is good as it had exponential O(2^n) time complexity which would cause severe performance issues for larger inputs.
Standards
- Algorithm Efficiency
- Time Complexity Optimization
| result = nth_fibonacci(n) | ||
| print(result) | ||
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| print(result) # Output: 5 |
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Duplicate Function Removal
The PR removes a duplicate iterative Fibonacci implementation. Having multiple implementations of the same function with different algorithms creates maintenance issues and confusion about which one to use.
Standards
- DRY Principle
- Code Duplication
- SOLID - Single Responsibility
WalkthroughThe Fibonacci computation was refactored to a memoized approach. A new helper nth_fibonacci_util(n, memo) was added, wrapped by nth_fibonacci(n) that initializes the memo table. Prior recursive and iterative implementations were removed. The main execution now prints the result with an inline expected output comment. Changes
Sequence Diagram(s)sequenceDiagram
participant Main
participant nth_fibonacci
participant nth_fibonacci_util
Main->>nth_fibonacci: nth_fibonacci(n)
nth_fibonacci->>nth_fibonacci_util: nth_fibonacci_util(n, memo)
alt memo hit
nth_fibonacci_util-->>nth_fibonacci: return memo[n]
else memo miss
nth_fibonacci_util->>nth_fibonacci_util: recurse(n-1, memo)
nth_fibonacci_util->>nth_fibonacci_util: recurse(n-2, memo)
nth_fibonacci_util->>nth_fibonacci_util: memo[n] = sum
nth_fibonacci_util-->>nth_fibonacci: return memo[n]
end
nth_fibonacci-->>Main: result
Estimated code review effort🎯 2 (Simple) | ⏱️ ~8 minutes Poem
✨ Finishing Touches
🧪 Generate unit tests
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Actionable comments posted: 1
🧹 Nitpick comments (3)
main.py (3)
29-29: Remove brittle inline “expected output” commentInline expected-output comments tend to drift and mislead. Prefer no comment here, or move the expectation into a unit test.
- print(result) # Output: 5 + print(result)
2-15: Recursive memoization risks RecursionError for large n; consider iterative or fast-doublingTop-down recursion has call depth O(n) and can hit Python’s recursion limit around n ≈ 1000. An iterative approach avoids this while staying O(n) time, O(1) space; fast-doubling is O(log n).
Iterative variant (outside the changed hunk):
def fibonacci_iter(n: int) -> int: if not isinstance(n, int) or n < 0: raise ValueError("n must be a non-negative integer") a, b = 0, 1 for _ in range(n): a, b = b, a + b return aYou can keep the current API by having nth_fibonacci call fibonacci_iter.
26-30: Add unit tests instead of relying on main print checksRelying on manual prints is brittle. Add tests for edge cases: n=0,1,5, negative inputs (expect ValueError), and a larger n to guard against regressions.
I can generate a unittest or pytest suite covering these cases. Want me to open a follow-up PR with tests?
| def nth_fibonacci(n): | ||
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| # Create a memoization table and initialize with -1 | ||
| memo = [-1] * (n + 1) | ||
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| # Call the utility function | ||
| return nth_fibonacci_util(n, memo) |
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Validate input: reject negative or non-integer n
Currently, passing a negative n returns a negative value (Line 4) which is incorrect for Fibonacci. Add input validation to ensure n is a non-negative integer.
Suggested replacement (outside the changed hunk):
def nth_fibonacci(n):
# Validate input early
if not isinstance(n, int) or n < 0:
raise ValueError("n must be a non-negative integer")
if n <= 1:
return n
memo = [-1] * (n + 1)
return nth_fibonacci_util(n, memo)🤖 Prompt for AI Agents
In main.py around lines 19 to 24, add input validation to reject negative or
non-integer n: check if n is an int and n >= 0 and raise ValueError("n must be a
non-negative integer") for invalid inputs; also handle the trivial cases by
returning n when n <= 1 before creating the memo array so the function doesn't
compute or return incorrect values for negative or small inputs.
Summary by CodeRabbit