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[class.access.base] No cv-qualification for access to inherited members #5068

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[class.access.base] No cv-qualification for access to inherited members #5068

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14 changes: 0 additions & 14 deletions source/classes.tex
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Original file line number Diff line number Diff line change
Expand Up @@ -4897,20 +4897,6 @@
\end{example}
\end{itemize}

\pnum
If a class member access operator, including an implicit
``\tcode{this->}'',
is used to access a non-static data member or non-static
member function, the reference is ill-formed if the
left operand (considered as a pointer in the
``\tcode{.}''
operator case) cannot be implicitly converted to a
pointer to the designating class of the right operand.
\begin{note}
This requirement is in addition to the requirement that
the member be accessible as designated.
\end{note}

\rSec2[class.friend]{Friends}%
\indextext{friend function!access and}%
\indextext{access control!friend function}
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10 changes: 10 additions & 0 deletions source/expressions.tex
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Expand Up @@ -4338,6 +4338,16 @@
Otherwise, the program is ill-formed.
\end{itemize}

\pnum
Let \tcode{C} be the cv-unqualified version of the type of \tcode{E1}.
The program is ill-formed if a prvalue of type ``pointer to \tcode{C}''
cannot be implicitly converted to a pointer to
the designating class\iref{class.access.base} of the right operand.
\begin{note}
This requirement is in addition to the requirement that
the member be accessible as designated.
\end{note}

\pnum
If \tcode{E2} designates a non-static member
(possibly after overload resolution),
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