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19 changes: 11 additions & 8 deletions solution/0000-0099/0066.Plus One/README.md
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<p>你可以假设除了整数 0 之外,这个整数不会以零开头。</p>

<p> </p>
<p>&nbsp;</p>

<p><strong>示例 1:</strong></p>
<p><strong>示例&nbsp;1:</strong></p>

<pre>
<strong>输入:</strong>digits = [1,2,3]
<strong>输出:</strong>[1,2,4]
<strong>解释:</strong>输入数组表示数字 123。
</pre>

<p><strong>示例 2:</strong></p>
<p><strong>示例&nbsp;2:</strong></p>

<pre>
<strong>输入:</strong>digits = [4,3,2,1]
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<p><strong>示例 3:</strong></p>

<pre>
<strong>输入:</strong>digits = [0]
<strong>输出:</strong>[1]
<strong>输入:</strong>digits = [9]
<strong>输出:</strong>[1,0]
<strong>解释:</strong>输入数组表示数字 9。
加 1 得到了 9 + 1 = 10。
因此,结果应该是 [1,0]。
</pre>

<p> </p>
<p>&nbsp;</p>

<p><strong>提示:</strong></p>

<ul>
<li><code>1 <= digits.length <= 100</code></li>
<li><code>0 <= digits[i] <= 9</code></li>
<li><code>1 &lt;= digits.length &lt;= 100</code></li>
<li><code>0 &lt;= digits[i] &lt;= 9</code></li>
</ul>

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<!-- description:start -->

<p>给你一个长度为 <code>n</code> 的整数数组 <code>nums</code> ,其中 <code>nums</code> 的所有整数都在范围 <code>[1, n]</code> 内,且每个整数出现 <strong>一次</strong><strong>两次</strong> 。请你找出所有出现 <strong>两次</strong> 的整数,并以数组形式返回。</p>
<p>给你一个长度为 <code>n</code> 的整数数组 <code>nums</code> ,其中 <code>nums</code> 的所有整数都在范围 <code>[1, n]</code> 内,且每个整数出现 <strong>最多</strong><strong>两次</strong> 。请你找出所有出现 <strong>两次</strong> 的整数,并以数组形式返回。</p>

<p>你必须设计并实现一个时间复杂度为 <code>O(n)</code> 且仅使用常量额外空间(不包括存储输出所需的空间)的算法解决此问题。</p>

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2 changes: 1 addition & 1 deletion solution/0400-0499/0480.Sliding Window Median/README_EN.md
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<pre>
<strong>Input:</strong> nums = [1,3,-1,-3,5,3,6,7], k = 3
<strong>Output:</strong> [1.00000,-1.00000,-1.00000,3.00000,5.00000,6.00000]
<strong>Explanation:</strong>
<strong>Explanation:</strong>
Window position Median
--------------- -----
[<strong>1 3 -1</strong>] -3 5 3 6 7 1
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<p>你是一位系统管理员,手里有一份文件夹列表 <code>folder</code>,你的任务是要删除该列表中的所有 <strong>子文件夹</strong>,并以 <strong>任意顺序</strong> 返回剩下的文件夹。</p>

<p>如果文件夹&nbsp;<code>folder[i]</code>&nbsp;位于另一个文件夹&nbsp;<code>folder[j]</code>&nbsp;下,那么&nbsp;<code>folder[i]</code>&nbsp;就是&nbsp;<code>folder[j]</code>&nbsp;的 <strong>子文件夹</strong> 。</p>
<p>如果文件夹&nbsp;<code>folder[i]</code>&nbsp;位于另一个文件夹&nbsp;<code>folder[j]</code>&nbsp;下,那么&nbsp;<code>folder[i]</code>&nbsp;就是&nbsp;<code>folder[j]</code>&nbsp;的 <strong>子文件夹</strong> 。<code>folder[j]</code>&nbsp;的子文件夹必须以&nbsp;<code>folder[j]</code> 开头,后跟一个 <code>"/"</code>。例如,<code>"/a/b"</code> 是&nbsp;<code>"/a"</code>&nbsp;的一个子文件夹,但&nbsp;<code>"/b"</code> 不是&nbsp;<code>"/a/b/c"</code> 的一个子文件夹。</p>

<p>文件夹的「路径」是由一个或多个按以下格式串联形成的字符串:<font color="#c7254e"><font face="Menlo, Monaco, Consolas, Courier New, monospace"><span style="font-size:12.6px"><span style="background-color:#f9f2f4">'/'</span></span></font></font>&nbsp;后跟一个或者多个小写英文字母。</p>

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<p>Given a list of folders <code>folder</code>, return <em>the folders after removing all <strong>sub-folders</strong> in those folders</em>. You may return the answer in <strong>any order</strong>.</p>

<p>If a <code>folder[i]</code> is located within another <code>folder[j]</code>, it is called a <strong>sub-folder</strong> of it.</p>
<p>If a <code>folder[i]</code> is located within another <code>folder[j]</code>, it is called a <strong>sub-folder</strong> of it. A sub-folder of <code>folder[j]</code> must start with <code>folder[j]</code>, followed by a <code>&quot;/&quot;</code>. For example, <code>&quot;/a/b&quot;</code> is a sub-folder of <code>&quot;/a&quot;</code>, but <code>&quot;/b&quot;</code> is not a sub-folder of <code>&quot;/a/b/c&quot;</code>.</p>

<p>The format of a path is one or more concatenated strings of the form: <code>&#39;/&#39;</code> followed by one or more lowercase English letters.</p>

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SORTracker tracker = new SORTracker(); // 初始化系统
tracker.add("bradford", 2); // 添加 name="bradford" 且 score=2 的景点。
tracker.add("branford", 3); // 添加 name="branford" 且 score=3 的景点。
tracker.get(); // 从好带坏的景点为:branford ,bradford 。
tracker.get(); // 从好到坏的景点为:branford ,bradford 。
// 注意到 branford 比 bradford 好,因为它的 <strong>评分更高</strong> (3 &gt; 2) 。
// 这是第 1 次调用 get() ,所以返回最好的景点:"branford" 。
tracker.add("alps", 2); // 添加 name="alps" 且 score=2 的景点。
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<p><strong>解释:</strong></p>

<p>子数组&nbsp;<code>[3]</code>&nbsp;的按位&nbsp;<code>OR</code> 值为&nbsp;<code>3</code>&nbsp;,所以我们返回 <code>1</code>&nbsp;。</p>

<p>注意,<code>[2]</code> 也是一个特别子数组。</p>
</div>

<p><strong class="example">示例 2:</strong></p>
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<p><strong>完美二叉树 </strong>是指所有叶子节点都在同一层级的树,且每个父节点恰有两个子节点。</p>

<p><strong>子树 </strong>是指树中的某一个节点及其所有后代形成的树。</p>

<p>&nbsp;</p>

<p><strong class="example">示例 1:</strong></p>
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<li>然而,区间组&nbsp;<code>[[1, 2], [3, 4]]</code>&nbsp;不是连通的,因为&nbsp;<code>(2, 3)</code>&nbsp;段没有被覆盖。</li>
</ul>

<p>返回在添加&nbsp;<strong>恰好一个</strong>&nbsp;新区间到数组后连通组的 <strong>最小</strong>&nbsp;数量。</p>
<p>返回在数组添加 <strong>恰好一个</strong> 新区间后,连通组的 <strong>最小</strong> 数量。</p>

<p>&nbsp;</p>

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