doocs · yanglbme · Oct 24, 2024 · Oct 24, 2024
diff --git a/solution/0500-0599/0555.Split Concatenated Strings/README_EN.md b/solution/0500-0599/0555.Split Concatenated Strings/README_EN.md
@@ -37,7 +37,7 @@ tags:
 <pre>
 <strong>Input:</strong> strs = [&quot;abc&quot;,&quot;xyz&quot;]
 <strong>Output:</strong> &quot;zyxcba&quot;
-<strong>Explanation:</strong> You can get the looped string &quot;-abcxyz-&quot;, &quot;-abczyx-&quot;, &quot;-cbaxyz-&quot;, &quot;-cbazyx-&quot;, where &#39;-&#39; represents the looped status.
+<strong>Explanation:</strong> You can get the looped string &quot;-abcxyz-&quot;, &quot;-abczyx-&quot;, &quot;-cbaxyz-&quot;, &quot;-cbazyx-&quot;, where &#39;-&#39; represents the looped status. 
 The answer string came from the fourth looped one, where you could cut from the middle character &#39;a&#39; and get &quot;zyxcba&quot;.
 </pre>
 

diff --git a/solution/3100-3199/3193.Count the Number of Inversions/README.md b/solution/3100-3199/3193.Count the Number of Inversions/README.md
@@ -27,7 +27,7 @@ tags:
 	<li><code>i &lt; j</code>&nbsp;且&nbsp;<code>nums[i] &gt; nums[j]</code></li>
 </ul>
 
-<p>请你返回&nbsp;<code>[0, 1, 2, ..., n - 1]</code>&nbsp;的&nbsp;<span data-keyword="permutation">排列</span> <code>perm</code>&nbsp;的数目，满足对 <strong>所有</strong>&nbsp;的&nbsp;<code>requirements[i]</code>&nbsp;都有&nbsp;<code>perm[0..end<sub>i</sub>]</code>&nbsp;恰好有&nbsp;<code>cnt<sub>i</sub></code>&nbsp;个逆序对。</p>
+<p>请你返回&nbsp;<code>[0, 1, 2, ..., n - 1]</code>&nbsp;的&nbsp;<span data-keyword="permutation">排列</span> <code>perm</code>&nbsp;的数目，满足对 <strong>所有</strong>&nbsp;的&nbsp;<code>requirements[i]</code>&nbsp;都满足&nbsp;<code>perm[0..end<sub>i</sub>]</code>&nbsp;中恰好有&nbsp;<code>cnt<sub>i</sub></code>&nbsp;个逆序对。</p>
 
 <p>由于答案可能会很大，将它对&nbsp;<code>10<sup>9</sup> + 7</code>&nbsp;<strong>取余</strong>&nbsp;后返回。</p>
 

diff --git a/solution/3300-3399/3308.Find Top Performing Driver/README.md b/solution/3300-3399/3308.Find Top Performing Driver/README.md
@@ -8,15 +8,15 @@ tags:
 
 <!-- problem:start -->
 
-# [3308. Find Top Performing Driver 🔒](https://leetcode.cn/problems/find-top-performing-driver)
+# [3308. 寻找表现最佳的司机 🔒](https://leetcode.cn/problems/find-top-performing-driver)
 
 [English Version](/solution/3300-3399/3308.Find%20Top%20Performing%20Driver/README_EN.md)
 
 ## 题目描述
 
 <!-- description:start -->
 
-<p>Table: <font face="monospace"><code>Drivers</code></font></p>
+<p>表：<font face="monospace"><code>Drivers</code></font></p>
 
 <pre>
 +--------------+---------+
@@ -28,11 +28,11 @@ tags:
 | experience   | int     |
 | accidents    | int     |
 +--------------+---------+
-(driver_id) is the unique key for this table.
-Each row includes a driver&#39;s ID, their name, age, years of driving experience, and the number of accidents they&rsquo;ve had.
+(driver_id) 是这张表的唯一主键。
+每一行包含一个司机 ID，他们的名字，年龄，驾龄年数，以及事故数。
 </pre>
 
-<p>Table: <font face="monospace"><code>Vehicles</code></font></p>
+<p>表：<font face="monospace"><code>Vehicles</code></font></p>
 
 <pre>
 +--------------+---------+
@@ -42,11 +42,11 @@ Each row includes a driver&#39;s ID, their name, age, years of driving experienc
 | fuel_type    | varchar |
 | mileage      | int     |
 +--------------+---------+
-(vehicle_id, driver_id, fuel_type) is the unique key for this table.
-Each row includes the vehicle&#39;s ID, the driver who operates it, the model, fuel type, and mileage.
+(vehicle_id, driver_id, fuel_type) 是这张表的唯一主键。
+每一行包含机动车 ID，驾驶员，车型，动力类型和里程数。
 </pre>
 
-<p>Table: <font face="monospace"><code>Trips</code></font></p>
+<p>表：<font face="monospace"><code>Trips</code></font></p>
 
 <pre>
 +--------------+---------+
@@ -56,29 +56,30 @@ Each row includes the vehicle&#39;s ID, the driver who operates it, the model, f
 | duration     | int     |
 | rating       | int     |
 +--------------+---------+
-(trip_id) is the unique key for this table.
-Each row includes a trip&#39;s ID, the vehicle used, the distance covered (in miles), the trip duration (in minutes), and the passenger&#39;s rating (1-5).
+(trip_id) 是这张表的唯一主键。
+每一行包含行程 ID，使用的机动车，覆盖的距离（以米计），行程市场（以分钟计），以及乘客评分（1-5）。
 </pre>
 
-<p>Uber is analyzing drivers based on their trips. Write a solution to find the <strong>top-performing driver</strong> for <strong>each fuel type</strong> based on the following criteria:</p>
+<p>优步正在基于司机的行程分析他们的情况。编写一个解决方案，根据下列标准来找到 <strong>每种动力类型</strong> 中&nbsp;<strong>表现最好的司机</strong>：</p>
 
 <ol>
-	<li>A driver&#39;s performance is calculated as the <strong>average rating</strong> across all their trips. Average rating should be rounded to <code>2</code> decimal places.</li>
-	<li>If two drivers have the same average rating, the driver with the <strong>longer total distance</strong> traveled should be ranked higher.</li>
-	<li>If there is <strong>still a tie</strong>, choose the driver with the <strong>fewest accidents</strong>.</li>
+	<li>一个司机的表现由他们行程的 <strong>平均评分</strong>&nbsp;计算。平均评分应该舍入到&nbsp;<code>2</code>&nbsp;位小数。</li>
+	<li>如果两个司机有相同的平均评分，<strong>里程数更多</strong>&nbsp;的司机评分更高。</li>
+	<li>如果 <strong>依旧持平</strong>，选择 <strong>事故数最少</strong>&nbsp;的司机。</li>
 </ol>
 
-<p>Return <em>the result table ordered by</em> <code>fuel_type</code> <em>in </em><strong>ascending</strong><em> order.</em></p>
+<p>返回结果表以&nbsp;<code>fuel_type</code> <strong>升序&nbsp;</strong>排序。</p>
 
-<p>The result format is in the following example.</p>
+<p>结果格式如下所示。</p>
 
 <p>&nbsp;</p>
-<p><strong class="example">Example:</strong></p>
+
+<p><strong class="example">示例：</strong></p>
 
 <div class="example-block">
-<p><strong>Input:</strong></p>
+<p><strong>输入：</strong></p>
 
-<p><code>Drivers</code> table:</p>
+<p><code>Drivers</code> 表：</p>
 
 <pre class="example-io">
 +-----------+----------+-----+------------+-----------+
@@ -90,7 +91,7 @@ Each row includes a trip&#39;s ID, the vehicle used, the distance covered (in mi
 +-----------+----------+-----+------------+-----------+
 </pre>
 
-<p><code>Vehicles</code> table:</p>
+<p><code>Vehicles</code> 表：</p>
 
 <pre class="example-io">
 +------------+-----------+---------+-----------+---------+
@@ -102,7 +103,7 @@ Each row includes a trip&#39;s ID, the vehicle used, the distance covered (in mi
 +------------+-----------+---------+-----------+---------+
 </pre>
 
-<p><code>Trips</code> table:</p>
+<p><code>Trips</code> 表：</p>
 
 <pre class="example-io">
 +---------+------------+----------+----------+--------+
@@ -117,7 +118,7 @@ Each row includes a trip&#39;s ID, the vehicle used, the distance covered (in mi
 +---------+------------+----------+----------+--------+
 </pre>
 
-<p><strong>Output:</strong></p>
+<p><strong>输出：</strong></p>
 
 <pre class="example-io">
 +-----------+-----------+--------+----------+
@@ -128,14 +129,14 @@ Each row includes a trip&#39;s ID, the vehicle used, the distance covered (in mi
 +-----------+-----------+--------+----------+
 </pre>
 
-<p><strong>Explanation:</strong></p>
+<p><strong>解释：</strong></p>
 
 <ul>
-	<li>For fuel type <code>Gasoline</code>, both Alice (Driver 1) and Charlie (Driver 3) have trips. Charlie has an average rating of 5.0, while Alice has 4.5. Therefore, Charlie is selected.</li>
-	<li>For fuel type <code>Electric</code>, Bob (Driver 2) is the only driver with an average rating of 4.5, so he is selected.</li>
+	<li>对于动力类型&nbsp;<code>Gasoline</code>，Alice（司机 1）和&nbsp;Charlie（司机 3）有行程。Charlie 平均评分为 5.0，而 Alice 为 4.5。因此，选择 Charlie。</li>
+	<li>对于动力类型&nbsp;<code>Electric</code>，Bob（司机 2）是唯一的司机，评分为 4.5，因此选择他。</li>
 </ul>
 
-<p>The output table is ordered by <code>fuel_type</code> in ascending order.</p>
+<p>输出表以&nbsp;<code>fuel_type</code>&nbsp;升序排序。</p>
 </div>
 
 <!-- description:end -->

diff --git a/solution/3300-3399/3327.Check if DFS Strings Are Palindromes/README.md b/solution/3300-3399/3327.Check if DFS Strings Are Palindromes/README.md
@@ -39,13 +39,11 @@ tags:
 
 <ul>
 	<li>清空字符串&nbsp;<code>dfsStr</code>&nbsp;并调用&nbsp;<code>dfs(i)</code>&nbsp;。</li>
-	<li>如果结果字符串&nbsp;<code>dfsStr</code>&nbsp;是一个 <strong>回文串</strong>&nbsp;，<code>answer[i]</code>&nbsp;为&nbsp;<code>true</code>&nbsp;，否则&nbsp;<code>answer[i]</code>&nbsp;为&nbsp;<code>false</code>&nbsp;。</li>
+	<li>如果结果字符串&nbsp;<code>dfsStr</code>&nbsp;是一个 <span data-keyword="palindrome-string">回文串</span>&nbsp;，<code>answer[i]</code>&nbsp;为&nbsp;<code>true</code>&nbsp;，否则&nbsp;<code>answer[i]</code>&nbsp;为&nbsp;<code>false</code>&nbsp;。</li>
 </ul>
 
 <p>请你返回字符串&nbsp;<code>answer</code>&nbsp;。</p>
 
-<p><strong>回文串</strong>&nbsp;指的是一个字符串从前往后与从后往前是一模一样的。</p>
-
 <p>&nbsp;</p>
 
 <p><strong class="example">示例 1：</strong></p>

diff --git a/solution/3300-3399/3328.Find Cities in Each State II/README.md b/solution/3300-3399/3328.Find Cities in Each State II/README.md
@@ -8,15 +8,15 @@ tags:
 
 <!-- problem:start -->
 
-# [3328. Find Cities in Each State II 🔒](https://leetcode.cn/problems/find-cities-in-each-state-ii)
+# [3328. 查找每个州的城市 II 🔒](https://leetcode.cn/problems/find-cities-in-each-state-ii)
 
 [English Version](/solution/3300-3399/3328.Find%20Cities%20in%20Each%20State%20II/README_EN.md)
 
 ## 题目描述
 
 <!-- description:start -->
 
-<p>Table: <code>cities</code></p>
+<p>表：<code>cities</code></p>
 
 <pre>
 +-------------+---------+
@@ -25,29 +25,30 @@ tags:
 | state       | varchar |
 | city        | varchar |
 +-------------+---------+
-(state, city) is the combination of columns with unique values for this table.
-Each row of this table contains the state name and the city name within that state.
+(state, city) 是这张表中值互不相同的列的组合。
+这张表的每一行包含州名和其中的城市名。
 </pre>
 
-<p>Write a solution to find <strong>all the cities</strong> in <strong>each state</strong> and analyze them based on the following requirements:</p>
+<p>编写一个解决方案来找到 <strong>每个州</strong>&nbsp;中的 <strong>所有城市</strong>&nbsp;并且根据下列条件分析它们：</p>
 
 <ul>
-	<li>Combine all cities into a <strong>comma-separated</strong> string for each state.</li>
-	<li>Only include states that have <strong>at least</strong> <code>3</code> cities.</li>
-	<li>Only include states where <strong>at least one city</strong> starts with the <strong>same letter as the state name</strong>.</li>
+	<li>用 <b>逗号分隔</b>&nbsp;字符串组合每一个州的所有城市。</li>
+	<li>只显示有 <strong>至少</strong>&nbsp;<code>3</code>&nbsp;个城市的州。</li>
+	<li>只显示&nbsp;<strong>至少有一个城市</strong>&nbsp;以与 <strong>州名相同字母开头</strong>&nbsp;的州。</li>
 </ul>
 
-<p>Return <em>the result table ordered by</em> <em>the count of matching-letter cities in <strong>descending</strong> order</em>&nbsp;<em>and then by state name in <strong>ascending</strong> order</em>.</p>
+<p>返回结果表以字母匹配城市的数量 <strong>降序</strong> 排序，然后按州名称 <strong>升序</strong> 排序的结果表。</p>
 
-<p>The result format is in the following example.</p>
+<p>结果格式如下所示。</p>
 
 <p>&nbsp;</p>
-<p><strong class="example">Example:</strong></p>
+
+<p><strong class="example">示例：</strong></p>
 
 <div class="example-block">
-<p><strong>Input:</strong></p>
+<p><strong>输入：</strong></p>
 
-<p>cities table:</p>
+<p>cities 表：</p>
 
 <pre class="example-io">
 +--------------+---------------+
@@ -71,58 +72,58 @@ Each row of this table contains the state name and the city name within that sta
 +--------------+---------------+
 </pre>
 
-<p><strong>Output:</strong></p>
+<p><strong>输出：</strong></p>
 
 <pre class="example-io">
 +-------------+-------------------------------------------+-----------------------+
 | state       | cities                                    | matching_letter_count |
 +-------------+-------------------------------------------+-----------------------+
 | Pennsylvania| Philadelphia, Pittsburgh, Pottstown       | 3                     |
-| Texas       | Dallas, Taylor, Temple, Tyler             | 2                     |
+| Texas       | Dallas, Taylor, Temple, Tyler             | 3                     |
 | New York    | Buffalo, Newark, New York City, Rochester | 2                     |
 +-------------+-------------------------------------------+-----------------------+
 </pre>
 
-<p><strong>Explanation:</strong></p>
+<p><strong>解释：</strong></p>
 
 <ul>
 	<li><strong>Pennsylvania</strong>:
 
     <ul>
-    	<li>Has 3 cities (meets minimum requirement)</li>
-    	<li>All 3 cities start with &#39;P&#39; (same as state)</li>
+    	<li>有 3 个城市（符合最低条件）</li>
+    	<li>所有的 3 个城市都以 'P' 开头（与州相同）</li>
     	<li>matching_letter_count = 3</li>
     </ul>
     </li>
     <li><strong>Texas</strong>:
     <ul>
-    	<li>Has 4 cities (meets minimum requirement)</li>
-    	<li>2 cities (Temple, Tyler) start with &#39;T&#39; (same as state)</li>
-    	<li>matching_letter_count = 2</li>
+    	<li>有 4 个城市（符合最低条件）</li>
+    	<li>3 个城市 (Taylor, Temple, Tyler) 以 'T' 开头（与州相同）</li>
+    	<li>matching_letter_count = 3</li>
     </ul>
     </li>
     <li><strong>New York</strong>:
     <ul>
-    	<li>Has 4 cities (meets minimum requirement)</li>
-    	<li>2 cities (Newark, New York City) start with &#39;N&#39; (same as state)</li>
+    	<li>有 4 个城市（符合最低条件）</li>
+    	<li>2 个城市 (Newark, New York City) 以 'N' 开头（与州相同）</li>
     	<li>matching_letter_count = 2</li>
     </ul>
     </li>
-    <li><strong>California</strong> is not included in the output because:
+    <li><strong>California</strong> 没有包含在输出表，因为：
     <ul>
-    	<li>Although it has 4 cities (meets minimum requirement)</li>
-    	<li>No cities start with &#39;C&#39; (doesn&#39;t meet the matching letter requirement)</li>
+    	<li>尽管它有 4 个城市（符合最低条件）</li>
+    	<li>没有城市以 'C' 开头（不符合字母匹配条件）</li>
     </ul>
     </li>
 
 </ul>
 
-<p><strong>Note:</strong></p>
+<p><strong>注意：</strong></p>
 
 <ul>
-	<li>Results are ordered by matching_letter_count in descending order</li>
-	<li>When matching_letter_count is the same (Texas and New York both have 2), they are ordered by state name alphabetically</li>
-	<li>Cities in each row are ordered alphabetically</li>
+	<li>结果以 matching_letter_count 降序排序。</li>
+	<li>当 matching_letter_count 持平（Texas 和 New York 都为 2），按州名字母序排序。</li>
+	<li>每一行的城市也以字母序排序。</li>
 </ul>
 </div>
 

diff --git a/solution/3300-3399/3328.Find Cities in Each State II/README_EN.md b/solution/3300-3399/3328.Find Cities in Each State II/README_EN.md
@@ -78,7 +78,7 @@ Each row of this table contains the state name and the city name within that sta
 | state       | cities                                    | matching_letter_count |
 +-------------+-------------------------------------------+-----------------------+
 | Pennsylvania| Philadelphia, Pittsburgh, Pottstown       | 3                     |
-| Texas       | Dallas, Taylor, Temple, Tyler             | 2                     |
+| Texas       | Dallas, Taylor, Temple, Tyler             | 3                     |
 | New York    | Buffalo, Newark, New York City, Rochester | 2                     |
 +-------------+-------------------------------------------+-----------------------+
 </pre>
@@ -97,8 +97,8 @@ Each row of this table contains the state name and the city name within that sta
     <li><strong>Texas</strong>:
     <ul>
     	<li>Has 4 cities (meets minimum requirement)</li>
-    	<li>2 cities (Temple, Tyler) start with &#39;T&#39; (same as state)</li>
-    	<li>matching_letter_count = 2</li>
+    	<li>3 cities (Taylor, Temple, Tyler) start with &#39;T&#39; (same as state)</li>
+    	<li>matching_letter_count = 3</li>
     </ul>
     </li>
     <li><strong>New York</strong>: