Add Pandas solution for 184. Department Highest Salary

solution/0100-0199/0184.Department Highest Salary/README.md

@@ -114,6 +114,31 @@ WHERE
     );
 ```
 
+### Pandas
+
+```python
+import pandas as pd
+
+
+def department_highest_salary(
+    employee: pd.DataFrame, department: pd.DataFrame
+) -> pd.DataFrame:
+    # Merge the two tables on departmentId and department id
+    merged = employee.merge(department, left_on='departmentId', right_on='id')
+
+    # Find the maximum salary for each department
+    max_salaries = merged.groupby('departmentId')['salary'].transform('max')
+
+    # Filter employees who have the highest salary in their department
+    top_earners = merged[merged['salary'] == max_salaries]
+
+    # Select required columns and rename them
+    result = top_earners[['name_y', 'name_x', 'salary']].copy()
+    result.columns = ['Department', 'Employee', 'Salary']
+
+    return result
+```
+
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solution/0100-0199/0184.Department Highest Salary/README_EN.md

@@ -116,6 +116,31 @@ WHERE
     );
 ```
 
+### Pandas
+
+```python
+import pandas as pd
+
+
+def department_highest_salary(
+    employee: pd.DataFrame, department: pd.DataFrame
+) -> pd.DataFrame:
+    # Merge the two tables on departmentId and department id
+    merged = employee.merge(department, left_on='departmentId', right_on='id')
+
+    # Find the maximum salary for each department
+    max_salaries = merged.groupby('departmentId')['salary'].transform('max')
+
+    # Filter employees who have the highest salary in their department
+    top_earners = merged[merged['salary'] == max_salaries]
+
+    # Select required columns and rename them
+    result = top_earners[['name_y', 'name_x', 'salary']].copy()
+    result.columns = ['Department', 'Employee', 'Salary']
+
+    return result
+```
+
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solution/0100-0199/0184.Department Highest Salary/Solution.py

@@ -0,0 +1,20 @@
+import pandas as pd
+
+
+def department_highest_salary(
+    employee: pd.DataFrame, department: pd.DataFrame
+) -> pd.DataFrame:
+    # Merge the two tables on departmentId and department id
+    merged = employee.merge(department, left_on='departmentId', right_on='id')
+
+    # Find the maximum salary for each department
+    max_salaries = merged.groupby('departmentId')['salary'].transform('max')
+
+    # Filter employees who have the highest salary in their department
+    top_earners = merged[merged['salary'] == max_salaries]
+
+    # Select required columns and rename them
+    result = top_earners[['name_y', 'name_x', 'salary']].copy()
+    result.columns = ['Department', 'Employee', 'Salary']
+
+    return result