Create code.py

2022-Freshers/Greedy-Job/code.py

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+n = int(input("Please enter the number of jobs: "))
+jobs = []
+for i in range(n):
+    start_time = int(input("Please enter start time: "))
+    end_time = int(input("Please enter end time: "))
+    profit = int(input("Please enter profit value: "))
+    jobs.append([start_time, end_time, profit])
+
+#Sort the jobs in ascending order of start time
+jobs.sort(key = lambda x:x[0])
+
+#Lokesh picks job with maximum profit
+max_profit = 0
+for job in jobs:
+    if job[2] > max_profit:
+        max_profit = job[2]
+        max_job = job
+
+#Remove the selected job from the jobs list
+jobs.remove(max_job)
+
+#Calculate the number of jobs and total earnings left for other employees
+number_jobs = len(jobs)
+total_earnings = 0
+for job in jobs:
+    total_earnings += job[2]
+
+print("Number of jobs left for other employees: ", number_jobs)
+print("Total earnings left for other employees: ", total_earnings)