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自动判断路由是前进还是后退,从而实现对应转场效果 #53

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自动判断路由是前进还是后退,从而实现对应转场效果 #53

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fe6a60e
自动判断路由为前进后退来实现对应转场效果
Mar 24, 2020
a0bb5b7
remove console.log
Mar 24, 2020
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19 changes: 13 additions & 6 deletions src/index.js
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Original file line number Diff line number Diff line change
Expand Up @@ -130,18 +130,26 @@ const plugin = {
}
} : null
})

var pathArr=[];//用于存放路由跳转记录
router.beforeEach((to, from, next) => {
route = to
let toDepth = to.path.split('/').filter(v => !!v).length
let fromDepth = from.path.split('/').filter(v => !!v).length

transitionType = toDepth > fromDepth ? 'forward' : 'back'
//第一次进入首页,记录首页路由
if(from.path=='/'){
pathArr.push(to.path);
}
//深度相同
if (toDepth === fromDepth) {
if (lastPath === to.path && toDepth < fromDepth) {
//队列中无记录则为前进,有则为返回,且清除返回之前的路由记录
var index=pathArr.indexOf(to.path)
if(index!=-1){
transitionType = 'back'
} else {
pathArr.splice(index+1,pathArr.length-index)
}else{
pathArr.push(to.path)
transitionType = 'forward'
}
//深度相同时禁用动画
Expand All @@ -150,11 +158,10 @@ const plugin = {

lastPath = from.path
}

//首次进入无效果
if (to.path === from.path && to.path === lastPath)
transitionType = 'first'

// 处理map选项
const enter = Object.keys(op.map).find(key => op.map[key].enter && op.map[key].enter.includes(from.name))
const leave = Object.keys(op.map).find(key => op.map[key].leave && op.map[key].leave.includes(to.name))
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