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Fix NaN in jax.nn.standardize due to negative variance #30426 #33496
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Summary of ChangesHello @nandan2003, I'm Gemini Code Assist1! I'm currently reviewing this pull request and will post my feedback shortly. In the meantime, here's a summary to help you and other reviewers quickly get up to speed! This pull request enhances the numerical stability of the Highlights
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Code Review
This pull request addresses a NaN issue in jax.nn.standardize that occurs when floating-point imprecision leads to a small negative variance. The proposed solution of using jnp.maximum(variance, epsilon) instead of variance + epsilon is a robust fix. It correctly clamps the variance at a small positive value, preventing the argument to rsqrt from becoming negative and thus avoiding NaNs in the output. The change is correct and improves the numerical stability of the function. I've added one minor suggestion for code cleanup.
Co-authored-by: gemini-code-assist[bot] <176961590+gemini-code-assist[bot]@users.noreply.github.com>
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Thanks for this – I don't think this is the correct fix for the issue. See my comment at #30426 (comment) |
Description
Fixes #30426.
jax.nn.standardizepreviously returnedNaNwhen the input array had a variance slightly less than 0 (due to floating point imprecision) but larger in magnitude than-epsilon. In these cases,variance + epsilonremained negative, causingrsqrtto produce NaNs.This PR changes the normalization logic to clamp the variance using
jnp.maximum(variance, epsilon)instead of adding epsilon. This ensures the denominator is always valid.Reproduction