infer correct type for schema.String<T>({ required: false }) #69
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…e })
When using schema.String<CustomType>({ required: false }) with only one
type parameter, TypeScript would default the second type parameter O to {}
instead of inferring it from the argument. This caused the inferred type
to be CustomType instead of CustomType | undefined.
Fixed by adding function overloads that specifically handle the
{ required: false } case, allowing the options type to be captured
correctly without requiring explicit type parameters.
🤖 Generated with [Claude Code](https://claude.com/claude-code)
Co-Authored-By: Claude Opus 4.5 <[email protected]>
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When using schema.String({ required: false }) with only one type parameter, TypeScript would default the second type parameter O to {} instead of inferring it from the argument. This caused the inferred type to be CustomType instead of CustomType | undefined.
Fixed by adding function overloads that specifically handle the { required: false } case, allowing the options type to be captured correctly without requiring explicit type parameters.
🤖 Generated with Claude Code