fix(ci): create npmrc directly in package directory for publishing

- Publish script now creates .npmrc in the package dir (binaries/...)
- Simplified GitHub Actions workflow
- npm publish runs from package dir, so needs .npmrc there

Author: moazbuilds

.github/workflows/build-binaries.yml

@@ -71,9 +71,4 @@ jobs:
         env:
           NODE_AUTH_TOKEN: ${{ secrets.NPM_TOKEN }}
           CI: true
-        shell: bash
-        run: |
-          echo "//registry.npmjs.org/:_authToken=$NODE_AUTH_TOKEN" > ~/.npmrc
-          echo "//registry.npmjs.org/:_authToken=$NODE_AUTH_TOKEN" > .npmrc
-          chmod 600 ~/.npmrc .npmrc
-          bun scripts/publish-platform.mjs --tag latest --access public
+        run: bun scripts/publish-platform.mjs --tag latest --access public

scripts/publish-platform.mjs

@@ -100,6 +100,15 @@ try {
     console.log(`${cyan}→${reset} Running in CI mode with NODE_AUTH_TOKEN\n`);
   }
 
+  // In CI mode, create .npmrc in the package directory
+  if (isCI && process.env.NODE_AUTH_TOKEN) {
+    const { writeFileSync } = await import('node:fs');
+    const npmrcPath = join(packageDir, '.npmrc');
+    const npmrcContent = `//registry.npmjs.org/:_authToken=${process.env.NODE_AUTH_TOKEN}`;
+    writeFileSync(npmrcPath, npmrcContent, { mode: 0o600 });
+    console.log(`${green}✓${reset} ${dim}Created .npmrc in package directory${reset}\n`);
+  }
+
   // Build publish command
   const publishCmd = dryRun
     ? `npm publish --dry-run --tag ${tag} --access ${access}`