build: skip build-ci on run-ci

When run `make run-ci` with CONFIG_FLAGS only set in prior
`make build-ci`, `make run-ci` will try to rebuild everything, instead
of re-use the built result from prior `make build-ci`.

Author: legendecas

.github/workflows/test-shared.yml

@@ -194,5 +194,6 @@ jobs:
             --arg benchmarkTools '[]' \
             ${{ endsWith(matrix.system, '-darwin') && '--arg withAmaro false --arg withSQLite false --arg extraConfigFlags ''["--without-inspector" "--without-node-options"]'' \' || '\' }}
             --run '
+                make -C "$TAR_DIR" build-ci -j4 V=1
                 make -C "$TAR_DIR" run-ci -j4 V=1 TEST_CI_ARGS="-p actions --measure-flakiness 9 --skip-tests=$CI_SKIP_TESTS"
             '

Makefile

@@ -638,7 +638,7 @@ build-ci: ## Build everything (CI).
 #
 # Using -j1 as the sub target in `test-ci` already have internal parallelism.
 # Refs: https://github.com/nodejs/node/pull/23733
-run-ci: build-ci ## Build and run all tests (CI).
+run-ci: ## Run all tests (CI).
 	$(MAKE) test-ci -j1
 
 .PHONY: test-release