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BUG: fix PeriodIndex.difference producing incorrect results #60992
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Original file line number | Diff line number | Diff line change |
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@@ -534,6 +534,22 @@ def shift(self, periods: int = 1, freq=None) -> Self: | |
) | ||
return self + periods | ||
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def _convert_can_do_setop(self, other): | ||
try: | ||
if isinstance(other, Index): | ||
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# Handle empty cases | ||
if other.empty: | ||
return super()._convert_can_do_setop(other) | ||
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# Convert non-PeriodIndex to PeriodIndex | ||
if not isinstance(other, PeriodIndex): | ||
other = PeriodIndex(other, freq=self.freq) | ||
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except (TypeError, ValueError): | ||
return super()._convert_can_do_setop(other) | ||
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return super()._convert_can_do_setop(other) | ||
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def period_range( | ||
start=None, | ||
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Original file line number | Diff line number | Diff line change |
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@@ -361,3 +361,16 @@ def test_union_duplicates(self): | |
freq="D", | ||
) | ||
tm.assert_index_equal(result, expected) | ||
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def test_difference_periodindex_with_index(self): | ||
# GH#58971 | ||
index1 = period_range("2022-01", periods=5, freq="M") | ||
index2 = pd.Index(["2022-02", "2022-03"]) | ||
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result1 = index1.difference(index2) | ||
expected1 = PeriodIndex(["2022-01", "2022-04", "2022-05"], freq="M") | ||
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. i think this is wrong and the result in main is correct. |
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tm.assert_index_equal(result1, expected1) | ||
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result2 = index2.difference(index1) | ||
expected2 = pd.Index([]) | ||
tm.assert_index_equal(result2, expected2) |
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are the affected Index objects object-dtype?